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sergij07 [2.7K]
3 years ago
13

Geometry help??????

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
Check the picture below.

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a bag contains 6 black marbles and 6 white marbles. What is the least number of marbles that you must choose, without looking, t
o-na [289]

Given:

Number of black marbles = 6

Number of white marbles = 6

Let's determine the least number of marbles that can be chosen to be certain that you have chosen two marble of the same color.

To find the least number of marble to be chosen to be cartain you have chosen two marbles of the same color, we have:

Total number of marbles = 6 + 6 = 12

Number of marbles to ensure at least one black marble is chosen = 6 + 1 = 7

Number of marbles to ensure at least one white marble is chosen = 1 + 6 = 7

Therefore, the least number of marbles that you must choose, without looking , to be certain that you have chosen two marbles of the same color is 7.

ANSWER:

7

6 0
1 year ago
2p-1<br>make p the subject​
jok3333 [9.3K]

Answer:

2p-1/p

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
Complete the dilation centered at A with a scale factor of 1/2.
ElenaW [278]

Answer:

A'=(5/2,-5/2)

therefore A'(2.5,-2.5)

Step-by-step explanation:

8 0
3 years ago
Simplify the expression.<br> 4² . 4². 4²
Ugo [173]

Answer:

16.16.16

Step-by-step explanation:

please let me know if I'm wrong

but I learned that you don't do 4×2 you have to multiply 4 twice by itself so it would be 16 because 4×4=16

3 0
3 years ago
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