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g100num [7]
3 years ago
12

We can find the length of DE using the Pythagorean Theorem:

Mathematics
2 answers:
Sloan [31]3 years ago
8 0
The answer is 

<span>C)  <span>DE = <span>(4 - 1)2 + (1 - 3)<span>2

rewriten 

</span></span></span></span>DE = sqrt (4 - 1)^2 + (1 - 3)^2
prohojiy [21]3 years ago
6 0
What's the difference between A) and C)??
There should be an E) because the correct answer would be in either of these forms:
{DE}^{2}  =  {(4 - 1)}^{2}  +  {(1 - 3)}^{2}  \:  \: or \\  DE  =  \sqrt{( {3}^{2}  +  {2}^{2} )} \:   \: or \\  {DE}^{2}  =  {(4 - 1)}^{2} +  {(3 - 1)}^{2}
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Mario travels 180 miles in 2.5 hours . If Mario travels at the same rate, how far can Mario travel in 1 hour ?
Dominik [7]

Answer:

i have no idea.

Step-by-step explanation:

thug life.

5 0
3 years ago
What is the common ratio of 128,320,800,2000
Delicious77 [7]
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4 years ago
Use the traditional algorithm. What is (+16 ) divided (+2 ??
Tamiku [17]

Answer:

8

Step-by-step explanation:

In this problem, you are dividing a positive by a positive, meaning the answer will also be positive.

16 ÷ 2 = 8

You can check your answer by multiplying:

8 × 2 = 16

7 0
3 years ago
The scheduled arrival time for a daily flight from Boston to New York is 9:30 am. Historical data show that the arrival time fol
mamaluj [8]

Answer:

a) E(A)=\frac{0+50}{2}=25 min

Sd(A) =\sqrt{208.3333 min^2}=14.43 min

b) P(A>25) = 1-P(A\leq 25)=1-\frac{25-0}{50-0}= 1-0.5 = 0.5

Step-by-step explanation:

Part a

Let A the random variable that represent "The arrival time (minutes) for a daily flight from Boston to New York ". And we know that the distribution of A is given by:

A\sim Uniform(a=0 ,b=50)

We select our starting point a=0 representing 9:05 AM and the amount of minutes between 9:05 am to 9:55 am are 50 ans for this reason b =50

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{0+50}{2}=25 min

And the variance is given by:

Var(A)= \frac{(b-a)^2}{12}=\frac{(50-0)^2}{12}=208.3333 min^2

And the standard deviation by definition is just the square root of the variance:

Sd(A) =\sqrt{208.3333 min^2}=14.43 min

Part b

If we convert 9:30 AM to our scale we know that we have 25 minutes between 9:05 AM and 9:30 AM.

For this case we want to find this probability: P(A>25)

And we can find this probability using the complement rule like this:

P(A>25) = 1-P(A\leq 25)

And we can use the cumulative distribution function given by:

F(A) = \frac{A-a}{b-a}

And we got:

P(A>25) = 1-P(A\leq 25)=1-\frac{25-0}{50-0}= 1-0.5 = 0.5

5 0
3 years ago
|t – 4| – 5 = 0 (please show work)
Snowcat [4.5K]
T is -1 or 9
|9-4|-5=0
|5|-5=0
or
|-1-4|-5=0
|-5|-5=0
|5|-5=0
4 0
3 years ago
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