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g100num [7]
3 years ago
12

We can find the length of DE using the Pythagorean Theorem:

Mathematics
2 answers:
Sloan [31]3 years ago
8 0
The answer is 

<span>C)  <span>DE = <span>(4 - 1)2 + (1 - 3)<span>2

rewriten 

</span></span></span></span>DE = sqrt (4 - 1)^2 + (1 - 3)^2
prohojiy [21]3 years ago
6 0
What's the difference between A) and C)??
There should be an E) because the correct answer would be in either of these forms:
{DE}^{2}  =  {(4 - 1)}^{2}  +  {(1 - 3)}^{2}  \:  \: or \\  DE  =  \sqrt{( {3}^{2}  +  {2}^{2} )} \:   \: or \\  {DE}^{2}  =  {(4 - 1)}^{2} +  {(3 - 1)}^{2}
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Solve by factoring... plz show the work. !<br>x^2+9+20. ? ​
Helen [10]

if you meant x^2+9x+20 then it is (x+4)(x+5) you know that because 4+5=9 and 4x5=20 using FOIL

6 0
3 years ago
The steps below show the incomplete solution to find the value of y for the equation 4y – 2y – 4 = –1 + 13:
Sunny_sXe [5.5K]
You add the 4 to both sides of the equation.
5 0
3 years ago
I need help with math. i attached a pic
wel

Answer:

C

Step-by-step explanation:

This one is quite easy. If you look angle M is slightly obtuse which means that it can't be A or B but it is to small to be D.

7 0
3 years ago
Read 2 more answers
How do you solve 12.42 ÷ - 4.8
yanalaym [24]
Its -2.5875

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4 0
3 years ago
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A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
3 years ago
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