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forsale [732]
3 years ago
13

We know that the expression is 4x+40. How much will the length of the garden increase by if it uses 50 feet of fencing in total?

Here is a photo to help.

Mathematics
2 answers:
Gelneren [198K]3 years ago
4 0

Answer:

240

Step-by-step explanation:

anygoal [31]3 years ago
3 0

Answer:

<u>240</u>

Since the expression is 4x + 40 we just substitute 50 in for x, so the new equation looks like this 4(50) + 40 which gets us 240.

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PilotLPTM [1.2K]
The 2 outside the brackets means that everything within the brackets needs to be multiplied by 2
8 0
3 years ago
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In the diagram m angle ACB = 61<br> Find m angle BCD
Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

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7 0
4 years ago
Read 2 more answers
What is the common ratio of 2, 10/3, 50/9
mojhsa [17]

The common ratio of 2, 10/3, 50/9 is \frac{10}{6}

<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take \frac{10}{3} and 2

\text { Then, common ratio }=\frac{\frac{10}{3}}{2}

\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}

Hence, the common ratio of the given series is \frac{10}{6}

6 0
4 years ago
Complete the puzzle by clicking on the puzzle piece that contains equivalent expression.
Liono4ka [1.6K]

Answer:

 -5 when ...

Step-by-step explanation:

The rules of exponents can help you simplify the given product.

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<h3>Application</h3>

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This expression does not match any of those offered.

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8 0
2 years ago
Which expression is equivalent to (4 x cubed) (2 x) superscript negative 4?
Shalnov [3]

Answer:

section covers somplifying algebraic expressions

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7 0
2 years ago
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