Answer:
The answer is "Option a"
Explanation:
This payment is equivalent to the regular rent formally specified by the same contract that grants the member the rights for a specified time. It used both the nominal lending rate and the lessor's conditional value, which provides the lower implied rate, and wrong choices can be described as follows:
- In option b, It is wrong because in this we assume the implicit rate is lessee.
- Option c and Option d both were wrong because It doesn't use the Iterative credit rate.
Answer:
Option D. float is the correct answer.
Explanation:
Decimal number contains decimal point. Out of all the given data types, float data type store the number with decimal point.
As the number has to be further used for calculations float ahs to be used. Because the numbers can also be stored in string but cannot be used for further calculations.
Hence,
Option D. float is the correct answer.
As specified in RFC5735, this is an address from the "link local" block. It is assigned to a network interface as a temporary address, for instance if no static address is configured and the DHCP server is not found.
If you boot your PC without a network cable, you'll probably end up with a 169.254.*.* address.
When creating a user-generated function, what procedure is followed d) all of the above.
<h3>
What are the three factors of user-described characteristic?</h3>
A user-described characteristic has 3 essential additives which might be characteristic declarations, characteristic definition and characteristic called.
The characteristic prototypes are used to inform the compiler approximately the variety of arguments and approximately the specified datatypes of a characteristic parameter, it additionally tells approximately the go-back kind of the characteristic. By this information, the compiler cross-assessments the characteristic signatures earlier than calling.
Read more about the prototype :
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Answer:
The owls population increased by 13 in one year
Explanation:
The given data on the owl population are as follows;
The number of new owls born = 20 (positive increase in population)
The number of owls that die = 10 (negative decrease in population)
The number of owls that enter the forest = 5 (positive increase in population)
The number of owls that left the forest = 2 (negative decrease in population)
Let 'w' represent the number of new owls born, let 'x' represent the number of owls that die, let 'y' represent the number of owls that enter the forest and let 'z' represent the number of owls that left the forest, we get;
The change in population, ΔP = w - x + y - z
By plugging in the values, we get;
ΔP = 20 - 10 + 5 - 2 = 13
The change in the population of owls in one year is an increase in 13 owls.
