Two samples of carbon come into contact. A heat transfer will occur between sample A and sample B. What must be true for heat to
2 answers:
Answer:
The average kinetic energy of A is greater than that of B.
Explanation:
The temperature of an object is directly proportional to the average kinetic energy of the particles in the object. For instance, for an ideal gas, we have
where
KE is the kinetic energy
k is the Boltzmann constant
T the absolute temperature of the gas
Therefore, this means that in a hotter object the average kinetic energy of the particles is higher than the average kinetic energy of the particles in a colder object.
Moreover, the laws of thermodynamics tell us that heat is always transferred from a hotter object (higher temperature) to a colder object (lower temperature).
In this problem heat is transferred from sample A to sample B. Therefore, this means that object A has higher temperature, and therefore, higher average kinetic energy. So the correct answer is
The average kinetic energy of A is greater than that of B.
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Answer : The enthalpy of the reaction = -1839.6 KJ
Solution : Given,
= -520.0 KJ/mole
= -1699.8 KJ/mole
The balanced chemical reaction is,
Formula used :
We know that the standard enthalpy of formation of the element is equal to Zero.
Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.
Now, put all the values in above formula, we get
= (-3399.6) + (1560)
= -1839.6 KJ
2.15 x 10⁻³mL
Explanation:
Given parameter:
Volume of blood sample in uL = 2.15uL
Conversion uL → mL
micro- and milli- are both prefixes of sub-units.
liter is a unit of volume of a substance.
micro - is 10⁻⁶
milli- is of the order 10⁻³
The problem is converting from micro to milli:
if we multiply 10⁻⁶ by 10³ we would have our milli;
1000uL = 1mL
2.15uL : 2.15uL x = 2.15 x 10⁻³mL
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