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murzikaleks [220]
3 years ago
9

A saturated solution of silver nitrate is prepared in 100g of water at 20c. The solution is then heated to 50c. How much more si

lver nitrate must now be added to obtain a saturated solution?
Chemistry
1 answer:
erastovalidia [21]3 years ago
7 0

Answer:

233 g.

Explanation:

  • It is known that:

The solubility of silver nitrate at 20.0°C is 222 g per 100 g of water.

The solubility of silver nitrate at 50.0°C is 455 g per 100 g of water.

<em>∴ We need to add (455 g - 222 g = 233 g) of AgNO₃ to obtain a saturated solution at 50.0°C.</em>

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If one adds 0.1 mol of the weak acid hf (pk_a = 3.2) to a solution with a ph = 2, which species would be most abundant and how m
zavuch27 [327]

F^{-} is most abundant and 6310 times more than HF.

<h3>What is a strong and weak acid?</h3>

When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.

When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.

The powerful acids include perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.

Given:

Pka=3..2

pH=7

Let the volume be 1 liter

[HF]=01 M

pH=pka+log \frac{F^{-}}{HF} \\\\7=3.2+log\frac{F^{-}}{HF} \\3.8=log\frac{F^{-}}{HF}\\ \frac{F^{-}}{0.1}=10^{3.8} \\F^{-}=630.95 M

Now,

\frac{F^{-}}{HF}=\frac{630.95}{0.1}\\ =6309.57

F-:HF= 6309.57:1

Therefore, the most abundant is F^{-}and has 6310 times more than HF is F^{-}.

To know more about strong and weak acids, visit: brainly.com/question/12811944

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4 0
1 year ago
Although _________________ are clearly dangerous psychoactive chemicals-drugs-semantic fiction portrays them otherwise.
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2 years ago
What will be produced at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2
natita [175]

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

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