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3 years ago

What are you guys doing:)

Mathematics

2 answers:

krek1111 [17]3 years ago

5 0

Answer:

math homework

Step-by-step explanation:

what about you?

lesantik [10]3 years ago

4 0

Lookin for free points kinda like this one whatcha doin?

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Pls show working 3 friends shared the driving on a long trip. Marla drove 7 miles more than Guido. Guido drove five times as far

olga2289 [7]

Step-by-step explanation:

Marla drove 567

Gudio drove 560

The trip was 679

5 0

2 years ago

Read 2 more answers

Pls help me for brainliest answer

Ket [755]

Answer with Step-by-step explanation:

$a)3n + 4 \\ \\n = 1 \\ 3 \times 1 + 4 \\ 3 + 4 \\ =7 \\ \\ n = 2 \\ 3 \times 2 + 4 \\ 6 + 4 \\ = 10 \\ \\ n = 3 \\ 3 \times 3 + 4 \\ 9 + 4 \\ = 13 \\ \\ n = 4 \\ 3 \times 4 + 4 \\ 12 + 4 \\ = 16 \\ \\ n = 10 \\ 3 \times 10 + 4 \\ 30 + 4 \\ = 34 \\$

So in this sequence,

1st term = 7

2nd term = 10

3rd term = 13

4th term = 16

10th term = 34

$b)4n - 5 \\ \\ n = 1 \\ 4 \times 1 - 5 \\ 4 - 5 \\ = - 1 \\ \\ n = 2 \\ 4 \times 2 - 5 \\ 8 - 5 \\ = 3 \\ \\ n = 3 \\ 4 \times 3 - 5 \\ 12 - 5 \\ = 7 \\ \\ n = 4 \\ 4 \times 4 - 5 \\ 16- 5 \\ = 11 \\ \\ n = 10 \\ 4 \times 10 - 5 \\ 40 - 5 \\ = 35$

In this sequence,

1st term = -1

2nd term = 3

3rd term = 7

4th term = 11

10th term =35

5 0

3 years ago

a stadium shaped like a hemisphere with a radius of 150 feet. last month the owners of the stadium paid $0.05 per cubic foot to

lesantik [10]

The formula for volume of a hemisphere is: V = 2/3 * π * r³

Volume = 2/3 x 3.14 x 150^3

Volume = 7,065,000 cubic feet.

Multiply the cost per cubic foot by the volume:

7,065,000 x 0.05 = 353,250

The total cost was $353,250

6 0

3 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$