Acceleration, distance, and time problem, please help!
1 answer:
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We know that
see the picture to better understand the problem
in the right triangle ABC
Applying the Pythagoras Theorem
AB²=BC²+AC²-------> BC²=AB²-AC²
AB=8 ft
AC=4 ft
BC²=8²-4²-----> BC²=48--------> BC=√48-------> BC=6.93 ft
the answer is
6.93 ft
see the picture to better understand the problem
in the right triangle ABC
Applying the Pythagoras Theorem
AB²=BC²+AC²-------> BC²=AB²-AC²
AB=8 ft
AC=4 ft
BC²=8²-4²-----> BC²=48--------> BC=√48-------> BC=6.93 ft
the answer is
6.93 ft
Solution:
<u>A few changes were made:</u>
- 4 as 4.00.
- 0.3 as 0.30
<u>New equation:</u>
- 4 + 0.3 + 0.09 = 4.00 + 0.30 + 0.09
<u>Solving the equation:</u>
- 4.00 + 0.30 + 0.09
- => 4.39 (Refer to image for work)
Correct option is B.
