Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer:
a
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Answer:
-1/2
Step-by-step explanation:
the slope of the first line is 2
to get the line perpendicular, you swap the numerator and denominator, then if positive make negative and the other way around
The correct answer is not up there. its -125a^7