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aliina [53]
3 years ago
8

Find the volume of the prism

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answers:

1.) 1/9 m cubed

Explanation: The formula is l x w x h. So 1/3 x 1/2 x 2/3.

2.) 15/16 ft cubed

Explanation: 5/4 x 3/2 x 1/2.

Hope it helps :)

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A trader made a profit of 24% by selling an article for 3,720cedis how much should he have sold it to make a profit of 48%​
arsen [322]
The answer is 7440
24%=3720
48%= 3720*2
48% = 7440
6 0
3 years ago
Let a and b be real numbers where ab+0. Which of the following functions could represent the graph below?
8090 [49]

Answer:

O f(x) = x(x – b) 3

Step-by-step explanation:

\huge\color{aqua}{\boxed{{\colorbox{black}{hope \: it \: helps}}}}

3 0
2 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
I Think it’s A ...It’s my Final..Am I Right is it A?
vladimir1956 [14]

Answer:

yes, your right

Step-by-step explanation:

6 0
3 years ago
8-6: MathXL for School: Practice & Problem Solving
notka56 [123]

Answer:

The Area of a circle is

\pi {r}^{2}

Therefore the Area of Circle A is

\pi {8}^{2}  \\ 201.06

Area of Circle B is

\pi {10}^{2}  \\ 314.16

Circle C

\pi {14}^{2}  \\ 615.75

Circle D

\pi {13}^{2}  \\ 530.93

3 0
3 years ago
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