I Think it’s A ...It’s my Final..Am I Right is it A?

Last question. 50 points!

Shkiper50 [21]

w=-1.5

w=2

Answer:

Solution given:

$\sqrt{2w²-19w+31}+2=7-2w$

again

keep square root alone

$\sqrt{2w²-19w+31}=7-2w-2$

solve subtraction of 7-2

$\sqrt{2w²-19w+31}=5-2w$

Squaring on both side

$(\sqrt{2w²-19w+31})²=(5-2w)²$

2w²-19w+31=5²-2*5*2w+4w²

take terms one side

2w²-19w+31-25+20w-4w²=0

-2w²+w+6=0

2w²-w-6=0

doing middle term factorisation

2w²-(4-3)w-6=0

2w²-4w+3w-6=0

take common from each two term

2w(w-2)+3(w-2)=0

(w-2)(2w+3)=0

either

w=2

or

W=-3/2=-1.5

3 0

3 years ago

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luda_lava [24]

Rational number are numbers which can be expressed in a ratio of two integers. Both numerator and denominator are whole numbers, where the denominator is not equal to zero.
An irrational number on the other hand is a number which cannot be expressed in a ratio of two integers. However there are similarities between them. For example: the product of both irrational numbers of born rational numbers can be rational number, both irrational and rational numbers can be negative and positive, and both can be expressed as a fraction.

4 0

3 years ago

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Suppose the number of hits a webpage receives follows a Poisson distribution. The average number of hits per minute is 2.4. What

REY [17]

Answer:

The probability that the page will get at least one hit during any given minute is 0.9093.

Step-by-step explanation:

Let X = number of hits a web page receives per minute.

The random variable X follows a Poisson distribution with parameter,

λ = 2.4.

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

Compute the probability that the page will get at least one hit during any given minute as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-\frac{e^{-2.4}(2.4)^{0}}{0!}\\=1-\frac{0.09072\times1}{1} \\=1-0.09072\\=0.90928\\\approx0.9093$

Thus, the probability that the page will get at least one hit during any given minute is 0.9093.

6 0

3 years ago

You roll a number cube with 6 sides two times. What is the probability of rolling a number greater than 2 and an odd number?

svetoff [14.1K]

Answer:

lol you've asked like 10 probability questions in 20 minutes i wonder what chapter you're studying

Step-by-step explanation:

4 0

3 years ago

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Dots sells t-shirts ($2) and shorts ($4). In April total sales were $456. People bought 4 times as many t-shirts as shorts. How

Doss [256]

Answer:

Dots sold 152 t-shirts and 38 shorts sold.

Step-by-step explanation:

Let t = t-shirts and s = shorts.

We know that people bought 4 times as many t-shorts as shorts, which can be set to the equation t = 4s

Since t-shirts cost $2, shorts cost $4, and the total sales was $456, we can set the equation 2t +4s = 456

So our two equations are:

t = 4s

2t + 4s = 456

Substitute t from the 1st equation into the 2nd:

2(4s) + 4s = 456

8s + 4s = 456

12s = 456

s = 38

There were 38 shorts sold.

Since we have the number of shorts, we can plug that back into the 1st equation to find the number of t-shirts sold:

t = 4s

t = 4(38)

t = 152

There were 152 t-shirts sold.

4 0

4 years ago