To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
36 and 48
a = b+12
a+b = 84
(b+12) + b =84
2b +12 = 84
2b = 72
b= 36
a = b + 12
a = 36 + 12
a = 48
6 goes into 516 86times.You only divide 516/6
Answer:
3x-18x^2+1
Step-by-step explanation:
(6x+1)(1-3x)
6x-18x^2+1-3x
6x-3x-18x^2+1
3x-18x^2+1
Hope this helps :)
The answer is D) s/cos55°