<span>To do these you will be adding or subtracting 2pi (or integer multiples of .
Since the given angles are in fraction form, it will help to have 2pi in fraction form, 2pi=10/5=6pi/3=4pi/2=18pi/9 NOTE: this>(/) stands for over like 1 over 2 EX. 1/2
too, so the addition/subtraction is easier.
Hint: When deciding if you have a number between 0 and 2pi, compare it to the fraction version of 2pi that you've been adding/subtracting.
For 17pi/5...
First we can see that 17pi/5 is more than 10pi/5 (aka 2pi). So we need to start subtracting: 17pi/5 - 10pi/5 = 7pi/5
Now we have a number between 0 and 10pi/5. So 7pi/5 is the co-terminal angle between 0 and 2pi.
I'll leave the others for you to do. Just remember that you might have to add or subtract multiple times before you get a number between 0 and 2pi.
P.S don't add or subtract at all if the number starts out between 0 and 2pi.</span>
9x1
You would add 2+7 which =9 then x+1 that’s 1 so it would be 9x1
Show me what u are working on
Answer:
<h3>A≈974.83</h3><h3>V Volume </h3><h3>2862</h3><h3>
Step-by-step explanation:</h3>
<h3>Using the formulas</h3><h3>A=4πr2</h3><h3>V=4</h3><h3>3πr3</h3><h3>Solving forA</h3><h3>A=π⅓(6V)⅔=π⅓·(6·2862)⅔≈974.83372</h3>
<h3>brainliest pls and ur welcome</h3>
