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3 years ago

Find the circumference of the given circle. Use 3.14 for pi, and round your answer to the nearest tenth.

Mathematics

1 answer:

N76 [4]3 years ago

7 0

Answer:

Step-by-step explanation:

Because multiply 18.8 and 3.14 and get a number with a decimal so round up and get 59 :)

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A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity

taurus [48]

Answer: 8.73 ft/s

Step-by-step explanation:

We have the following equation that models the motion of the rock:

$h(t)=-16t^{2}+64t+180$

Where $h(t)$ is the height of the rock at a time $t$ .

Now, if $h(t)=48 ft$ we can find $t$ and then the velocity of the rock at that height:

$48=-16t^{2}+64t+180$

Rearranging the equation:

$-16t^{2}+64t+132=0$

Multiplying the equation by -1:

$16t^{2}-64t-132=0$

Solving with the quadratic formula $t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ , where $a=16$ , $b=-64$ , $c=-132$ .

$t=\frac{-(-64)\pm\sqrt{(-64)^{2}-4(16)(-132)}}{2(16)}$

Choosing the positive result of the equation:

$t=5.5 s$

Since velocity $V$ is defined as the traveled distance $h(t)$ in a given time $t$ , we have:

$V=\frac{h(t)}{t}$

$V=\frac{48 ft}{5.5 s}$

$V=8.727 ft/s \approx 8.73 ft/s$ This is the velocity of the rock at the height of 48 feet

7 0

2 years ago

Find the area of the rectangle

aksik [14]

Hope it works for you

4 0

3 years ago

Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,

posledela

Answer:

number of multiplies is n!
n=10, 3.6 ms
n=15, 21.8 min
n=20, 77.09 yr
n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

mpy[n] = n·mp[n-1]

mpy[2] = 2

So, ...

mpy[n] = n! . . . n ≥ 2

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0

3 years ago

If a = 5 in the right triangle what is the value of b and c

Nadya [2.5K]

Answer:

b=5√3, c=10

Step-by-step explanation:

30-60-90 triangle

c=2a

b=a√3

6 0

3 years ago

What is the difference between the following two regression equations? ModifyingAbove y with caret equals b 0 plus b 1 xy=b0+b1

Leona [35]

Answer:

A. The first equation is for sample data; the second equation is for a population.

Step-by-step explanation:

The first equation is y = $b_0 + b_1x$ , this is the equation for sample data as the intercept ( $b_0$ ) and the slope parameter( $b_1$ ) both are calculated then we have got this and these values are not taken as given.

The Second equation is $y = \beta _0 +\beta _1x$ , this is the equation for population data as we can't calculate these $\beta _0$ and $\beta _1$ as we take these values as given and also we do testing for $\beta$ parameter using t test and it is sure that testing is always done on population data not on sample data.

5 0

3 years ago