Answer:
b)The standard normal distribution has a mean of 0 and a standard deviation of 1, while a nonstandard normal distribution has a different value for one or both of those parameters.
Step-by-step explanation:
The standard normal distribution, ( and associated tables ) N (0,1) where 0 is the mean and 1 the standard deviation, is a model representative of all other nonstandard normal distribution. Therefore we apply such concepts and tebles in the solution of problems concerning normal distribution
First, let's re-arrange to slope-intercept form.
x + 8y = 27
Subtract 'x' to both sides:
8y = -x + 27
Divide 8 to both sides:
y = -1/8x + 3.375
So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.
So the slope of the perpendicular line will be 8.
Now we can plug this into point-slope form along with the point given.
y - y1 = m(x - x1)
y - 5 = 8(x + 5)
y - 5 = 8x + 40
y = 8x + 45
The solutions of the function are:
- When f(x) = -4, the solution is -4
- When f(x) = -2, the solution is -5/2
- When f(x) = 0, the solution is -1
<h3>How to solve for the equation </h3>
The equation is given as
When x = -4
3/4 * -4 -1
= -12/4 - 1
= -4
When x = -2
3/4*(-4) - 1
= -6/4 - 1/1
Take the lcm
-10/4
= -5/2
When x = 0
3/4(0) - 1
= -1
When f(x) = -4, the solution is -4
When f(x) = -2, the solution is -5/2
When f(x) = 0, the solution is -1
Read more on real numbers here:
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