Question 3 of 10

Mathematics

1 answer:

iragen [17]3 years ago

6 0

Answer:

Question 3 of 10 The answer should be 7

Step-by-step explanation:

The reason is because if it is out of 100 7/100 is still 7%

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There are five students of different ages. Their median age is 13 years A) what are two possibilities for the ages of the three

Levart [38]

A) the median is the middle measurement. Their ages could be 13, 14 and 15.
B) 2 students must be younger than 13
C) Like I said, the median is the middle measurement. If you have a list of numbers, you have to order them and take the middle number.

:) Have a nice day and maybe consider grading this answer brainliest? <3

6 0

3 years ago

Assume there are 365 days in a year.

Dahasolnce [82]

The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.

To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.

4 0

3 years ago

Joe can weed the garden twice as fast as his sister Janet. Together they can weed the garden in 2 hours. How long would it take

scoundrel [369]

Answer:

Joe: 3 hrs

Janet: 6hrs

Step-by-step explanation:

joe takes x hours

so in 1 hr he does 1/x of the garden

janet takes 2x hours

so in 1 hr she does 1/(2x) of the garden

In one hour together they do 1/2 of the garden

1/x + 1/(2x) = 1/2

2/(2x) + 1/(2x) = 1/2

3/(2x) = 1/2

Cross multiply

6 = 2x

x = 3

Joe: 3 hrs

Janet: 6hrs

4 0

3 years ago

The athletic departments at 10 randomly selected U.S. universities were asked by the Equal Employment Opportunity Commission to

Lesechka [4]

Answer: Mean = 3.5 , median = 2.5, mode = 2, geometric mean = 2.74

Median is the most appropriate measure of central tendency.

The least appropriate = mean

Yes there is an outlier.

Step-by-step explanation:

Given responses : 5, 4, 2, 1, 1, 2, 10, 2, 3, 5.

First arrange them in increasing order, $\sqrt[10]{1\times1\times2\times2\times2\times3\times4\times5\times5\times10 }\\\\=\sqrt[10]{24000} \approx2.74$