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maria [59]
3 years ago
13

Joe can weed the garden twice as fast as his sister Janet. Together they can weed the garden in 2 hours. How long would it take

each of them working alone?
A:\frac{1}{x}
Mathematics
1 answer:
scoundrel [369]3 years ago
4 0

Answer:

Joe: 3 hrs

Janet: 6hrs

Step-by-step explanation:

joe takes x hours

so in 1 hr he does 1/x of the garden

janet takes 2x hours

so in 1 hr she does 1/(2x) of the garden

In one hour together they do 1/2 of the garden

1/x + 1/(2x) = 1/2

2/(2x) + 1/(2x) = 1/2

3/(2x) = 1/2

Cross multiply

6 = 2x

x = 3

Joe: 3 hrs

Janet: 6hrs

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Purchased a book rs 500 sold 20%profit find its actual profit and sel<br>ling price​
umka2103 [35]

Answer:

Selling price=rs.600.

Profit of rs=100.

Step-by-step explanation:

C.P=500; profit%=20%

S.P.=100+profit%×C.P/100

S.P=120×500/100

=rs.600

S.P>C.P

Profit S.P-C.P

600-500=100

he gained for rs.100.

7 0
3 years ago
Find the x and y intercepts. Write your answer as x =<br> y =<br> 2x + 5y = 10
Ann [662]
The x-intercept is present where y = 0

2x + 5y - 10 = 0
2x - 10 = -5y
2x - 10 = -5(0)
2x = 10
x = 5

The y-intercept is present where x = 0

2x + 5y = 10
2x + 5y - 10 = 0
5y - 10 = -2(0)
5y = 10
y = 2
6 0
3 years ago
HELP FOR BRAINLESS !!!!
garik1379 [7]

Answer:

the blue one

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Hi there,<br> I need help to solve the perimeter and the surface area of this shape.<br> Thanks!
leonid [27]

Answer:  Perimeter = 6π ≈ 18.84

                         Area = 15π ≈ 47.10

<u>Step-by-step explanation:</u>

This is a composite of a big semicircle with diameter of 10 --> radius (r) = 5

plus a medium semicircle with diameter of 6 --> r = 3

minus a small semicircle with diameter of 4 --> r = 2

Perimeter of a semicircle = \dfrac{1}{2}(2\pi r)=\pi r

P_{big}=\pi (5)\quad =5\pi\\P_{medium}=\pi (3)\quad =3\pi\\P_{small}=\pi (2)\quad =2\pi\\P_{composite} =5\pi+3\pi -2\pi\\.\qquad \qquad =\large\boxed{6\pi}

Area of a semicircle = \dfrac{1}{2}(\pi r^2)

A_{big}=\dfrac{1}{2}\pi (5)^2\quad =12.5\pi\\\\A_{medium}=\dfrac{1}{2}\pi (3)^2\quad =4.5\pi\\\\A_{small}=\dfrac{1}{2}\pi (2)^2\quad =2\pi\\\\A_{composite} =12.5\pi+4.5\pi -2\pi\\\\.\qquad \qquad =\large\boxed{15\pi}

8 0
3 years ago
Jen has read 4/5 of a book. The next day she read 2/3 of what she had left. What fraction of the book is left to read?
Nostrana [21]

Answer:

1/15

Step-by-step explanation:


3 0
3 years ago
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