I need help, if your gonna spam go ahead and skip this.

The table shows the number of balls, by sport, in the gym. Sports Number of balls Basketball 2 Dodgeball 18 Soccerball 8 Tennis

ankoles [38]

Answer:

Option A is correct.

Step-by-step explanation:

No of Balls in Basketball = 2

No of Balls in Dodge ball = 18

No of Balls in Soccer ball = 8

No of Balls in Tennis ball = 14

$\frac{No.\:of\:Soccer\:ball}{No.\:of\:Tennis\:ball}=\frac{8}{14}=\frac{4}{7}$

Ratio of Soccer balls to Tennis balls = 4 : 7

⇒ For every 4 Soccer ball, there are 7 Tennis ball.

$\frac{No.\:of\:Basket\:ball}{No.\:of\:Dodge\:ball}=\frac{2}{18}=\frac{1}{9}$

Ratio of Basket ball to Dodge Ball = 1 : 9

⇒ For every 1 Basket ball, there are 9 Dodge balls.

Therefore, Option A is correct.

6 0

3 years ago

What is the value of C? 14 = -2C - 6 – 3C

icang [17]

Answer:

C = -4

Step-by-step explanation:

First, combine like terms (terms with the same amount of variables):

14 = -2C - 3C - 6

14 = (-2C - 3C) - 6

14 = (-5C) - 6

Isolate the variable, C. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operation, and equals:

Parenthesis

Exponents & Roots

Multiplication

Division

Addition

Subtraction.

First, add 6 to both sides:

14 (+6) = -5C - 6 (+6)

14 + 6 = -5C

-5C = 20

Next, divide -5 from both sides:

(-5C)/-5 = (20)/-5

C = 20/-5

C = -4

-4 is your value for C.

~

7 0

3 years ago

Read 2 more answers

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

2 years ago

Find the solution of this system of equations.

solmaris [256]

X=5+y

Substitute the value of x in second equation
28x – 9y= -12
28 (5+y)-9y =-12
140 +28y -9y =-12
140 +19y= -12
19y = - 152
y= -8

Now let's find the value of x using y

x= 5+y
x= 5 + (-8)
= -3

So,
x= -3
y=-8

3 0

4 years ago

This is a bit confusing for me. I understand how the whole X axis and Y axis works, and various graphs, but for some reason the

Dafna1 [17]

Your coordinates are (x,y), here you just need to figure what 'x' is given that 'y' is equal to -3. So, just plug in -3 for 'y' in the equation and then solve for 'x', like so: 4x + 5(-3) = -7 ... then just use algebra to solve for what 'x' has to be. Hope this helps!

7 0

3 years ago