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xxTIMURxx [149]
3 years ago
6

The polynomial y=x^2+4x+4 has a repeated factor. True or False?

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
True the factor is x+2
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Daniel has a beginning balance of $675 in his checking account. He writes two checks for $530 and $200. He has a deposit of $340
GenaCL600 [577]
$675.00 - $530.00 = $145.00
$145.00 - $200.00 = $55.00 negative balance, amount short.
$55.00 + 340.00 = $285.00 positive balance after deposit.
$285.00 - $29.00 = $256.00 new balance
Daniel has a new balance of $256.00
7 0
3 years ago
Any 10th grader solve it <br>for 50 points​
kkurt [141]

Answer:

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., a_{1}=A and common difference=D

The nth term can be written as

a_{n}=A+(n-1)D

pth term of given arithmetic progression is a

a_{p}=A+(p-1)D=a

qth term of given arithmetic progression is b

a_{q}=A+(q-1)D=b and

rth term of given arithmetic progression is c

a_{r}=A+(r-1)D=c

We have to prove that

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0

Now to prove LHS=RHS

Now take LHS

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)

=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)

=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)

=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}

=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}

=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

\neq 0

ie., RHS\neq 0

Therefore LHS\neq RHS

ie.,\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  

Hence proved

5 0
3 years ago
If anyone could help answer this question that would be great.
lys-0071 [83]
I believe the answer is 64
First break it off into 2 rectangles on is 4 width and 10 length other is 8 length and 10 width. Then multiple to find area 10•4=40 8•3=24 then add 40+24= 64
3 0
3 years ago
The Wares want to buy a new computer. The regular price is $1,049. The store is offering a 20% discount and a sales tax of 4.25%
MariettaO [177]

Answer:

so if you offer 20% off of 1,049 you get 209.8. If the tax is 4.25% then do the math -._-. (thinking)... 200.8835 and just do the lil bit of math to find your answer.

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
The school cafeteria has eight very large cans of tomato sauce for making pizza.
BlackZzzverrR [31]

Answer:

The Answer is that there is less than 50 Liters of sauce in the 2 cans.

Step-by-step explanation:

Given: 2 Gallons of sauce

How many Liters in 2 gallons?

There are 3.7854 liters per gallon. Multiply to get the total liters in 2 gallons:

2 * 3.7854 = 7.5708 Liters.

7.5708 is less than 50 Liters. Therefore, there is less than 50 Liters in the 2 gallons of sauce.

Hope this helps!! Have an Awesome day!!! :-)

8 0
3 years ago
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