Draw segments - 5 to A, A to the point of intersection of Band C and from from the point of intersection of B, C upto 2. It will form a square with each side 8 units and four triangles.

Subtracting the area of 4 four triangles from the area of the square will give you the area of the required shape.

Area of the shape

$= {8}^{2} - \frac{1}{2} \times 3 \times 6 - \frac{1}{2} \times 5 \times 2 - \frac{1}{2} \times 2 \times 3\\ - \frac{1}{2} \times 2 \times 5 \\ \\ = 64 - 3 \times 3 - 5 \times 1 - 1\times 3 - 1 \times 5 \\ \\ = 64 - 9 - 5 - 3 - 5 \\ \\ = 64 - 22 \\ = 42 \: {units}^{2}$

3 0

3 years ago

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Can someone help me understand how to solve a two variable equation I am really lost

Llana [10]

Easiest method solving 2 unknowns is Substitution.
So there will normally be 2(ormore)equations given.
Say
X+Y= a
bX=cY + d
a b c d are numbers they give
So first we rearrange the first equation
X = a - Y
No we substitute this into the 2nd equation so that we can get Y
since we know X = a-Y,
b(a-Y) = cY + d
we rearrange and we can find Y for this, it is just Y and numbers
hence finding Y, we sub the value for Y into X = a-Y and we get X also .

7 0

3 years ago

A. 20<br> b. 5<br> c. 40<br> d. 45

Rina8888 [55]

Answer:

C, 40

Step-by-step explanation:

You can set up the equation as 20+4x=180

180 is the total angle of the line

4x=160 and divide each side by 4

x=40

6 0

3 years ago

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