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vivado [14]
2 years ago
10

What are the values of a and b

Mathematics
1 answer:
sammy [17]2 years ago
6 0

Answer:

a equal to five.b equal to three

b=3

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I need help with this. I've tried to type out this problem, but it comes out wrong, so I uploaded a picture:
tatuchka [14]

answer: 6.4

work:

Solve the problem.

Let's start by solving the numerator,

(5 + 3)² <em>step one: add 5 + 3 </em>

(8)² <em>step two: simplify 8²</em>

64

now, let's simplify our denominator

1 + 2⁵ - 23 <em>step one: simplify 2⁵.</em>

1 + 32 - 23 <em>step two: add 1 + 32.</em>

33 - 23 <em>step three: subtract 33 - 23</em>

10.

now, put the numerator back over the denominator.

64/10

let's simplify by dividing, we get 6.4.

<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>


4 0
3 years ago
Can someone plz help Me?
hammer [34]

Answer:

A

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3 0
2 years ago
Read 2 more answers
Angel lives 3 3 4 blocks to the east of school. Tyrone lives 7 1 4 blocks to the west of Angel. Nadeem lives 8 blocks to the eas
Vladimir79 [104]

Answer:

3 1/2

Step-by-step explanation:

Given that:

Angel lives 3 3/4 blocks to the east of school

Tyrone lives 7 1/4 blocks to the west of Tyrone

Nadeem lives 8 blocks to the east of Tyrone.

Determining each of their homes in terms of distance from school :

Angel = 3 3/4 blocks from school

Tyrone = 7 1/4 blocks to the west of angel

Hence, distance from school will be :

7 1/4 - 3 3/4 = 3 1/2 blocks to the west of school

Nadeem = 8 blocks to the east of Tyrone :

Distance from school will be:

8 - 3 1/2 = 4 1/2 to the east of school.

Hence, 3 1/2 to the west of school is the closet distance of the three.

Hence, Tyrone lives closest to school

8 0
3 years ago
Which expression is equivalent to (q^4)^-3/q^-15 for all values of q where the expression is defined?
vodka [1.7K]

Answer: (h)q^3

Step-by-step explanation:

4 0
3 years ago
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
3 years ago
Read 2 more answers
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