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3 years ago

Which of the following is an equation of the line that has a slope of 1/3 and passes through the point (-6, 2)?

Mathematics

1 answer:

sineoko [7]3 years ago

3 0

Answer:

y-2=1/3(x+6)

Step-by-step explanation:

y-2=1/3(x-(-6))

y-2=1/3(x+6)

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The equation P = 21 + 2w can be used to find the perimeter of a rectangle. A 1 point rectangular shaped playground is enclosed b

nalin [4]

Answer:

130 m

Step-by-step explanation:

Given:

P = 2l + 2w
P = 500 m

Length is:

l = 120 m

Substitute values and solve for w:

500 = 2*120 + 2w
2w = 500 - 240
2w = 260
w = 260/2
w = 130 m

5 0

3 years ago

CAN ANYONE ANSWER THIS CORRECTLY???

Alisiya [41]

B, D, E are appropriate choices.

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A ray can be named by its (one) end-point and any other point on the ray. Since there are an infinite number of points on the ray, it can be named an infinite number of ways.

4 0

3 years ago

For questions 8 – 10, answer the questions about tangent-tangent angles.

olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

= $\frac{1}{2}(220-140)$

= $\frac{1}{2}(80)$

= 40°

9). Following the same rule as above,

Angle formed between two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

125 = $\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]$

250 = $[m(\text{arc ZWY})-m(\text{arc ZY})]$

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = $\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])$

= $\frac{1}{2}(254-106)$

= $\frac{148}{2}$

= 74°

4 0

2 years ago

Help please! Will give brainlest!

stira [4]

The answer is 17/22 17/20 because of the fractions

6 0

3 years ago

Read 2 more answers

Please help !! Geometry homework. Will mark brainliest answer !

sergeinik [125]

For this case we have:

By trigonometric property we have:

$Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}$

Where:

$Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x$

Substituting:

$Cosine(x)=\frac{12}{13}$

Clearing x we have:

$x =Cosine^{-1}(\frac{12}{13})$

Thus, the equation is: $x =Cosine^{-1}(\frac{12}{13})$

Answer:

$x =Cosine^{-1}(\frac{12}{13})$

3 0

2 years ago

Which of the following is an equation of the line that has a slope of 1/3 and passes through the point (-6, 2)? ​

Which of the following is an equation of the line that has a slope of 1/3 and passes through the point (-6, 2)?