If you multiply the dark inside one and the outside one then add them up it will give you the answer!<span />
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
3/5*8/9=8/15; A
Explanation:
First, you want to multiply both of the numerators together. 3*8=24.
Then, you want to multiply both of the denominators together. 5*9=45.
If you put the numerator and the denominator together, it comes out to be 24/45.
Lastly, you want to simplify 24/45. Divide those both by 3, and you get 8/15.
Hope that helps!
Answer:D!
Step-by-step explanation: Okay my bad u was trying to understand.Soooo 6:1.75 is a ratio of 6 to 1.75.Basically a different saying of 6/1.75.Well if u divide the fraction you will get about 3.42.Now we just take all of the answers and just divide all of them.boom 12/3.5 is also 3.42!Therefore D is your answer!
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Answer:
See attachment
Step-by-step explanation:
On attachment
