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Mekhanik [1.2K]
2 years ago
10

Solve 2sin ^2x-sin x-1=0

Mathematics
1 answer:
tia_tia [17]2 years ago
4 0
Consider, pls, the suggested solution.

Answer:
\left[\begin{array}{ccc}x=(-1)^{n+1}* \frac{ \pi}{6} + \pi n\\ \ x= \frac{ \pi}{2} +2 \pi n\end{array}

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densk [106]

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7 0
2 years ago
Please help, i don’t understand this at all.
zubka84 [21]
So, standard form basically takes the shape of Ax+By=C. You want all of your variables to be on the left side and your constant on the right. There can also be no fractions!

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first we get rid of the fraction by multiplying both sides of the equation by 2:
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now all there is left to do is get x to the other side by adding it to both sides:
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3 years ago
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