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garik1379 [7]
3 years ago
5

Mi hermano jueja al tenis ____________ (every now and then).

Mathematics
2 answers:
lesya [120]3 years ago
7 0

Answer:

B. de vez en cuando.

Step-by-step explanation:

dem82 [27]3 years ago
3 0

Answer:

B. de vez en cuando

Step-by-step explanation:

the literal transalation for "every now and then" in spanish is de vez en cuando.  Plus im am a native spanish speaker ;)

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Sarah already had 45 stamps in her collection and she gets 7 new stamps each month how long will it take before she has 129 stam
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The answer is:  " 12 months " .
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Explanation:
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What is the greatest common factor of 42, 56, and 112
VashaNatasha [74]

Answer: gcf, hcf, gcd (42; 112) = 14 = 2 × 7: greatest (highest) common factor (divisor), calculated.

Step-by-step explanation:

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What do you predict the solution for the system 5x-6y=7 and 6x-7y=8 will be ?<br>​
Alenkinab [10]
System of Linear Equations entered :

[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :

-6y + 5x = 7 -7y + 6x = 8

Solve equation [2] for the variable x


[2] 6x = 7y + 8

[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]

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[1] - y/6 = 1/3
[1] - y = 2
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8 0
3 years ago
Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your
lilavasa [31]

We have the equation:

y=a\cdot b^x

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}

Now, we use the point (2, 108/25) to calcualte b:

\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}

Then, we can write the equation as:

y=3\cdot(\frac{6}{5})^x

5 0
1 year ago
Use trial and improvement to find the solution to this positive equation
Novay_Z [31]
It's 3.01 sorry wrong question please forgive me
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3 years ago
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