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3 years ago

The Tran Family drove 1,246 miles during a vacation that lasted 14 days. How many miles on average did they drive each day? :3

2 answers:

8 0

Hey there!

To solve this problem, divide the numbers 1,246 and 14 . . .

1,246 ÷ 14 = 89 ←

Once you divide the miles and days, you will find your answer (89).

The correct answer is 89.

They drove 89 miles each day on average.

I hope this helps you.
Have a great day! :)

Svetllana [295]3 years ago

6 0

To find the average miles they drove each day, divide the total amount of miles by the number of days they drove.

1246 / 14 = 89

The Tran Family drove an average of 89 miles every day.

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The width of a rectangle is 8y- 1.5 feet and the length is 1.5y+9 feet. Find the perimeter of the rectangle.

lyudmila [28]

Answer:

$P=19y+15$

Step-by-step explanation:

Step one:

Given data

dimension of the rectangle

Width = 8y-1.5

Length = 1.5y+9

Required

The expression to represents the Perimeter

Step two:

the perimeter of a rectangle is expressed as

$P= 2L+2W\\\\P=2(1.5y+9)+2(8y-1.5)\\\\P=3y+18+16y-3\\\\$

collect like terms

$P=3y+16y+18-3\\\\P=19y+15$

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3 years ago

Tonya plans to join a fitness club. She researched the costs to join different clubs in her area and found that there is a linea

Ne4ueva [31]

Answer: 1 club - Club 2

Step-by-step explanation:

You can find the monthly rates by deducting the cost at 12 months from the cost at 24 months and dividing it by 12.

Club 1 Club 2 Club 3

= (432 - 216) / 12 = (390 - 210) / 12 = (504 - 252) / 12

= $18 = $15 = $21

Multiply these rates by 6 months and any club total cost at 6 month that differs from your answer has a joining fee.

Club 1; Club 2; Club 3

= 18 * 6 = 15 * 6 = 21 * 6

= $108 = $90 = $126

Same as total cost at Joining fee of $30; No joining fee as

6 months so no joining 120 - 90 = $30 this is the same

fee. as total cost at 6

months.

5 0

3 years ago

Read 2 more answers

Find the radius and diameter of circle A, if the endpoints of the radius are (-2, -1) and (6,4).

AleksandrR [38]

Step-by-step explanation:

$length \: between \: ( - 2, - 1) \: and \: (6,4) \\ = \sqrt{(x _{1} - x _{2} )² + (y _{1} - y _{2})² } \\ = \sqrt{( - 2 - 6)²+ ( - 1 - 4)²} \\ = \sqrt{64 + 25} \\ = \sqrt{100} \\ = 10 \: units \\ radius = 10 \: units \\ diameter = 2 \times radius \\ d = 2 \times 10 \\ d = 20 \: units$

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2 years ago

In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH

solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)

Consider triangles CBH and BCK. In these triangles,

∠CBH ≅ ∠BCK (from equality (*));
∠HCB ≅ ∠KBC, because m∠B = m∠C;
BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0

3 years ago

Translate this phrase into an algebraic expression. 73 less than twice Jose's height Use the variable to represent Jose's height

Luba_88 [7]

Answer:

x-73

Step-by-step explanation:

Let x=Jose's height. If it says "less than," then that is subtraction. Since Jose's height is not defined, there is no specific number that can be used to describe "73 less than twice Jose's height," so I use the variable x, and then subtract 73.

8 0

2 years ago