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nlexa [21]
2 years ago
7

Plzz help me plzz! I am timed

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0

Answer:

The second answer, and fifth answer

Step-by-step explanation:

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Vesnalui [34]

Answer:

E

Step-by-step explanation:

it's the correct answer I'm sure of

6 0
3 years ago
Choose the right answer.
kramer

Answer:

In this section, we discuss box-and-whisker plots and the five key values. The key values are called a five-number summary, which consists of the minimum, first quartile, the set is put into increasing order, divides the data into two equal parts. First, we put the values in the data set into increasing order: 3, 5, 7, 8, 12, 13, the middle score for a set of data that has been arranged in order from least to greatest. A box-and-whisker plot shows the distribution of a set of data along with... Quartiles are values that divide a set of data into four equal parts. The second Quartile ( designated Q2) also called the median or the 50th percentile (cuts data set in half ).

Step-by-step explanation:

5 0
2 years ago
What is the sum of 7.8 and 7.02
Neporo4naja [7]
The sum of 
7.8 and 7.02 would be 
14.82

because 
  7.8 
+7.02
------------
14.82


hope this helps :)  



4 0
3 years ago
Read 2 more answers
Solve for x and y.<br> L<br> 60°<br> 14<br> (6x + 7y)<br> M<br> N<br> 2(2x + 1)
notsponge [240]
X=3 Y=4 is your answer
6 0
3 years ago
3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
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