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34kurt
2 years ago
8

Please help ill mark branilest

Mathematics
2 answers:
son4ous [18]2 years ago
8 0

I think it's the third choice :)) the one you currently have

MrRissso [65]2 years ago
5 0
It is the third one you already have it good job
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Convert the circle to standard form.<br><img src="https://tex.z-dn.net/?f=%20%7B9x%7D%5E%7B2%7D%20%20%2B%20%20%7B9y%7D%5E%7B2%7D
lara31 [8.8K]

Answer:

(x + 1)² + (y + 1)² = (√6)²

Step-by-step explanation:

Group the x- and y- terms together:

9x^2 + 18x + 9y^2 + 9y = 36

Factor out the coefficient 9:

x^2 + 2x + y^2 + y = 4

Complete the square of x^2 + 2x and then do the same for y^2 + 2y:

x^2 + 2x + 1 - 1 + y^2 + 2y + 1 - 1 = 4

Rewrite x^2 + 2x + 1 as the square of the binomial x + 1:

(x + 1)^2 + (y + 1)^2 - 2 = 4

Collect the constant terms on the right side:

(x + 1)^2 + (y + 1)^2 = 6

Rewrite 6 as (√6)^2:

(x + 1)² + (y + 1)² = (√6)² is the equation in standard form (x - h)² + (y - k)² = r²

Completing the square is done as follows:  x^2 + 2x

Start with x^2 + 2x

1.  Take half of the coefficient of x, which results in 2/2, or 1

2.  Square this result and add it to, and subtract it from x^2 + 2x

     x^2 + 2x + 1 - 1

3.  Rewrite the first three terms as the square of a binomial:  

     x^2 + 2x + 1 - 1 = (x + 1)² - 1.

Do the same for y² + 2y.

7 0
2 years ago
Help me please thank you
Natali5045456 [20]

Try the last one; it doesn't mention anything foreign.

3 0
3 years ago
A parallelogram has vertices E(-8,3), F(2,-2), G(-1,3), and H(-5,-2). What are the coordinates of the midpoint of each diagonal?
d1i1m1o1n [39]
Hello,
Please, see the attached file.
Thanks.

6 0
3 years ago
Find the measure of angle A.<br> Please help??
Over [174]

Answer:

4

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
I need help with this. Thanks <br><br><br> I need to find the degree
scoundrel [369]

Answer:

  119.05°

Step-by-step explanation:

In general, the angle is given by ...

  θ = arctan(y/x)

Here, that becomes ...

  θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

__

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

  Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

  θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

3 0
3 years ago
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