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2 years ago

Find the area of the triangle ! include the unit in the answer (cm) (cm2) (cm3)

Mathematics

2 answers:

zavuch27 [327]2 years ago

5 0

Answer:

the answer is 34 $cm^{2}$

Step-by-step explanation:

You would treat the question as 2 different problems, a small and big triangle. You use the the Pythagorean theorem to find base of the big triangle which would be 13.4(rounded) meaning that the base for the small triangle would be 3.6. From here you would use the equation to find the area of a triangle a = 1/2 bh. Find the area of each triangle separately and then add them together to get 34.

Sphinxa [80]2 years ago

3 0

Answer:476

Step-by-step explanation:

if you multiply 14 times 17 times 4 it equals 952 but if you divide it it equals 476

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You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?

Rasek [7]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}$

$\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61$

5 0

2 years ago

If a farmer sells 9.8 KL of apples and pears at the farmers market. 4/5 of this weight is apples,and the rest are pears. How man

faltersainse [42]

Answer:

1.96

Step-by-step explanation:

A farmer sells 9.8 kl of apples and pears

4/5 of this weight is apples, while the rest are pears

Therefore the wight of pears can be calculated as follows

Let x represent the weight of pears

9.8= 4/5×9.8 + x

9.8= 0.8×9.8+x

9.8= 7.84+x

9.8-7.84= x

x= 1.96

8 0

3 years ago

Given: The coordinates of rhombus WXYZ are W(0, 4b), X(2a, 0), YO, -4b), and Z(-2a, 0).

Shkiper50 [21]

Answer:

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

Step-by-step explanation:

W (0 , 4b) X ( 2a , 0) Y (0 , -4b) Z (-2a , 0)

M (midpoint of WX) : ( (0 + 2a)/2 , (4b + 0)/2) i. e. (a , 2b)

N (midpoint of XY) : ( (2a + 0)/2 , (0 - 4b)/2) i. e. (a , - 2b)

O (midpoint of YZ) : ( (0 - 2a)/2 , (- 4b + 0)/2) i. e. (- a , - 2b)

P (midpoint of ZW) : ( (0 - 2a)/2 , (4b + 0)/2) i. e. (- a , 2b)

MN: length = 2b + 2b = 4b MN segment perpendicular to x axis (slope undefined)

NO: length = a + a = 2a NO segment parallel to x axis (slope = 0)

OP: length = 2b + 2b = 4b OP segment perpendicular to x axis (slope undefined)

PM: length = a + a = 2a NO segment parallel to x axis (slope = 0)

MN = OP and MN // OP and MN ⊥ PM

NO = PM and NO // PM and NO ⊥ OP

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

please draw graph to prove

8 0

2 years ago

Solve the Law of Cosine: c^2 = a^2+ b^2 - 2abcosC for cos C.

Andrew [12]

Answer:

The Law of Cosine : cos C = $\frac{a^{2}+ b^{2}-c^{2}}{2ab}$

Step-by-step explanation:

See the figure to understand the proof :

Let A Triangle ABC with sides a,b,c,

Draw a perpendicular on base AC of height H meet at point D

Divide base length b as AD = x -b and CD = x

By Pythagoras Theorem

In Triangle BDC And In Triangle BDA

a² = h² + x² ( 1 ) c² = h² + (x-b)²

c² = h² + x² + b² - 2xb ...(. 2)

From above eq 1 and 2

c² = (a² - x²) + x² + b² - 2xb

or, c² = a² + b² - 2xb .....(3)

Again in ΔBDC

cos C = $\frac{BD}{BC}$

Or, cos C = $\frac{x}{a}$

∴ x= a cos C

Now put ht value of x in eq 3

I.e, c² = a² + b² - 2ab cos C

Hence , cos C = $\frac{a^{2}+ b^{2}-c^{2}}{2ab}$ Proved Answer

6 0

2 years ago

Subtract.

Advocard [28]

(6k + 2) - (3k - 2)= 6k + 2 - 3k + 2 = 3k + 4

5 0

3 years ago

Read 2 more answers