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OverLord2011 [107]

3 years ago

7

64,000 in a fraction

2 answers:

earnstyle [38]3 years ago

4 0

Answer:

undefined

Step-by-step explanation:

Flura [38]3 years ago

4 0

Answer:

64/1000

Step-by-step explanation:

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2.5 What is the difference between relational understanding and instrumental

Afina-wow [57]

Answer:

Instrumental understanding – having a mathematical rule and being able to apply and manipulate it. Relational understanding – having a mathematical rule, knowing how to use it AND knowing why it works.

Step-by-step explanation:

Instrumental understanding involves “memorising which problems a method works for and which not, and also learning a different method for each new class of problems” (Skemp 1987, p. 159), is a desire to know “some kind of rule for getting the answer” (p. 155) so that a student can “latch on it and ignore the rest”

3 0

2 years ago

(PLEASE ANSWER ASAP!)

shtirl [24]

Mode: 43 & 81 ( They both appeared the most amount of times)
Range: 41 (Subtract the largest number with the smallest number)
Mean: 58
Min: 40 (Q1)
Max: 81 (Q3)
Med: 54 (Q2)

Hope this helps!!!

5 0

3 years ago

Write a real-life word problem that involves one-variable equation. Discuss how you would go about solving this problem.

GalinKa [24]

Answer:

A waiter at a restaurant earns 10 dollars per hour. How much money is earned in 4 hours?

Equation: m = 10h

m = money earned

h = hours worked

Plug in 4 for (h)

m = 10(4)

m = 40 dollars

The waiter earns 40 dollars in 4 hours.

Step-by-step explanation:

5 0

3 years ago

What is the taxidistance between (2,11) and (7,10)<br> 4<br> 6<br> 7<br> 26

Scilla [17]

X difference: 7-2 = 5 y difference: 11-10 = 1 Add up those results: 5+1 = 6

Answer Is 6

4 0

3 years ago

At time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t

larisa [96]

Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. $s(t) = -t^3+15t^2-72 t$

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

$v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)$

a) v(t) =0 when t = 4 or 6

b) $a(t) = -6t+30$

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

$s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110$

i.e. 110 miles (distance cannot be negative)

3 0

3 years ago