What is the answer i really need help

A chapter begins on page 114 and ends on page 859. How many pages are in the chapter?

Usimov [2.4K]

745, because u need to subtract both to find pages isolated

3 0

3 years ago

A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace

Alex787 [66]

D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20

5 0

4 years ago

Substitute this equation x+3y=18 & -x-4y=-25

sveticcg [70]

Answer:

{x,y} = {3/7,-43/7}

Step-by-step explanation:

System of Linear Equations entered :

[1] x + 3y = -18

[2] -x + 4y = -25

Graphic Representation of the Equations :

3y + x = -18 4y - x = -25

Solve by Substitution :

// Solve equation [1] for the variable x

[1] x = -3y - 18

// Plug this in for variable x in equation [2]

[2] -(-3y-18) + 4y = -25

[2] 7y = -43

// Solve equation [2] for the variable y

[2] 7y = - 43

[2] y = - 43/7

// By now we know this much :

x = -3y-18

y = -43/7

// Use the y value to solve for x

x = -3(-43/7)-18 = 3/7

Solution :

{x,y} = {3/7,-43/7}

5 0

3 years ago

If AB + BC = AC, and A, B,and C are collinear, which of the following is true?

antiseptic1488 [7]

What choice of answers do you have?

8 0

3 years ago

Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure

Marina CMI [18]

Answer:

a) $P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

b) $P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.12,0.009)$

Where $\mu=0.12$ and $\sigma=0.009$

We are interested on this probability

$P(0.11$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by: