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motikmotik
3 years ago
5

a gym membership is advertised to cost 630 per year . what is the cost per mouth of the gym menbership

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

52 1/2 OR 52.5

Step-by-step explanation:

You divide 630 by the number of months in a year, 12. 630 / 12 = 52.5. So the answer is 52.5 (Dollars, cents, whatever money label it is).

Hope that helps!

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2x+4y=1 3x-5y=7<br><br> Find the value of x and y<br><br> Thank you
Rashid [163]

Answer:


2x+4y=13x-5y=7

Too Many Equal Signs



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   2x+4y=13x-5y=7


Program Execution Terminated


 

Tiger was not able to solve for your input:2x+4y=13x-5y=7

Submit your own solution!Step-by-step explanation:


8 0
3 years ago
1. what is the distributive property of 8×59. 2.what is the distributive property of 9×84. 3. what is the distributive property
kherson [118]
1.8x59 is 472
8(59)

2.9x84 is 756
9(84)

3.6x78 is 468
6(78)

4.7x96 is 672
7(96)
7 0
3 years ago
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Is (7,8) a solution of the equation 2x+y=6
victus00 [196]

no it is not i don’t think that adds up correctly if u do the problem

7 0
3 years ago
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Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
-28=p+21<br> Please help I don’t understand
gayaneshka [121]

Answer: -7

Step-by-step explanation:

3 0
3 years ago
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