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viktelen [127]
3 years ago
10

frac{2}{3} \times 5\frac{2}{4} " alt=" \frac{2}{3} \times 5\frac{2}{4} " align="absmiddle" class="latex-formula">
find the product and simpifly​
Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

3  2/3

Step-by-step explanation:

change 5 2/4 into an improper fraction:  5(4)+2 over 4  =  22/4

\frac{2}{3} x \frac{22}{4} = \frac{44}{12}

\frac{44}{12} can be simplified by dividing top and bottom by 4 to get 11/3 or 3 2/3

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What is this can anyone help me
Solnce55 [7]

g(x) = (x - 3)² - 4

given f(x) is shifted a units horizontally to the right → f(x) → f(x - a)

If f(x) is shifted by a units horizontally left → f(x) → f(x + a)

If f(x) is shifted by b units vertically up → f(x) → f(x) + b

If f(x) is shifted by b units vertically down → f(x) → f(x) - b

The vertex (0, 0) of f(x) has shifted to (3, -4)

that is 3 units horizontally to the right and 4 units vertically down

hence g(x) = (x - 3)² - 4


4 0
3 years ago
All my information is "solve"...no other instructions were given...
Dahasolnce [82]
I assume we are solving for x see attachment.

8 0
3 years ago
Read 2 more answers
Given BE= 2x+6 and ED= 5x-12 in a parallelogram ABCD, find BD
Brrunno [24]
1.BE = 2x + 6
   ED = 5x - 12
2. To get the entire side of BD, we must add both half's which equals to the entire length.
3. 2x + 6 + 5x - 12
4.Add like terms.
2x + 5x = 7x
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5. So, we have 7x - 6

=7x - 6
3 0
3 years ago
How to solve an algebraic expression by putting values of unknown
andrey2020 [161]

Answer:

Step-by-step explanation:

Algebraic expressions tend to have atleast one unknown variable in it. In order to solve the expression we need to assign a fixed value to that variable or isolate it if the expression is equal to another value. For example, in the following expression we have the variable x, if we give it a value of 5 we simply solve like a regular expression...

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3 0
2 years ago
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