Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Answer:
y = 7
Step-by-step explanation:
An equilateral triangle has all its sides to be equal..
so.
10 = x
10 = y + 3
y = 10 - 3
y = 7
Answer:
3x + y = -16
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given a system of equations are
5x+6y =-5
- 2x - 5y = -11
multiply '1' and Adding two system of equtions
+ 1 (5x + 6y = -5)
+ 1 (<u> -2x - 5y = -11)</u>
<u> 3x + y = -16 </u>
<u>Final answer:-</u>
5x + 6y = -5
<u> -2x - 5y = -11</u>
<u> 3x + y = -16 </u>
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Answer:
Folding 6 loads
Step-by-step explanation: