Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form. (2 points)

A(n) _____ is a government-backed mortgage.

Alecsey [184]

CONVENTIONAL LOAN. LIKE FHA AND VA

7 0

2 years ago

A jar contains 5 orange marbles, 3 black marbles, and 6 brown marbles. event a = drawing a brown marble on the first draw event

tino4ka555 [31]

The probability of event A and event B IS 15/91.

What is the probability?

Probability determines the odds that a random event would occur. The odds lie between 0 and 1.

The probability of event A = number of brown marbles / total number of marbles

= 6/14

The probability of event B = number of orange marbles / total number of marbles -1

= 5/13

P(A and B) =6/14 x 5/13

= 30/182

= 15/91

To know more about probability visit:

brainly.com/question/3142525

#SPJ4

7 0

1 year ago

Find the lateral surface area of the figure.

Brut [27]

Surface area of the cylinder = 816.4 sq. ft.

Solution:

Height of the cylinder = 21 ft

Diameter of the cylinder = 10 ft

Radius of the cylinder = 10 ÷ 2 = 5 ft

Use the value of $\pi$ = 3.14

Surface area of the cylinder = $2 \pi r h+2 \pi r^{2}$

Substitute the given values in the surface area formula, we get

Surface area of the cylinder $$=2\times3.14\times 5\times 21+2 \times3.14\times 5^2$

$=659.4+157$

$=816.4$ ft²

Hence the surface area of the cylinder is 816.4 sq. ft.

7 0

2 years ago

Read 2 more answers

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$