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nalin [4]
3 years ago
9

How do I solve this math problem?

Mathematics
2 answers:
blondinia [14]3 years ago
8 0
Subtract 1 from both sides of the equal sign. (3-11 and 11-11) So, now you only have -8 = 1/2b ... Next, divide 1/2 from both sides (because you need to make the variable, b, be the only thing on one side of the equal sign) and you get -4 = b . So, your answer is -4.
Alina [70]3 years ago
6 0
You would subtract 11 on both sides of the equation.
Then multiply the reciprocal of 1/2 which is 2.
And you should get -16 as your answer <span />
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-11 2/3 x (-4 1/5)=?
qaws [65]

Answer:

49

Step-by-step explanation:

(-11\frac{2}{3} )  * (-4\frac{1}{5} ) = (-\frac{35}{3} )(-\frac{21}{5})

(-\frac{35}{3} )(-\frac{21}{5})=\frac{735}{15}

\frac{735}{15}=49

6 0
3 years ago
The ratio 2.5m to 60cm can be written in the form 1:n find the value of n. someone please help asap
Svetach [21]

Answer:

24

Step-by-step explanation:

2.5 divided by 2.5 equals 1. So 60 divided by 2.5 equals 24.

5 0
3 years ago
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Yati has a coin box containing some coins. 40% of the coins are 20-cent coins and the rest are 50-cent coins.
lana66690 [7]

The fraction that should be removed is 1/5.

<h3>How to calculate the fraction?</h3>

It should be noted that from the information, 40% of the coins are 20-cent coins and the rest are 50-cent coins. Those that are 50 cent will be:

= 100 - 40%

= 60%

The fraction that's should be removed will be:

= 2/5 - x = 1/5

x = 2/5 - 1/5

x = 1/5

The fraction that should be removed is 1/5.

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7 0
2 years ago
3. You have $20 to spend at the snack bar. All of the
Ket [755]
A) $17.50
B) $11.25
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3 0
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Find the constant of variation (k) where y varies directly with x. y = 2, when<br> X = 6.
ExtremeBDS [4]

Answer:

The graph below models the value of a $20,000 car t years after it was purchased.

                    Value of Car

A graph titled Value of Car has years on the x-axis and Dollars on the y-axis. A line curves down and goes through points (0, 20,000), (4, 10,000), and (14, 2,000).

Which statement best describes why the value of the car is a function of the number of years since it was purchased?

Each car value, y, is associated with exactly one time, t.

Each time, t, is associated with exactly one car value, y.

The rate at which the car decreases in value is not constant.

There is no time, t, at which the value of the car is 0.

Step-by-step explanation:

7 0
3 years ago
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