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nalin [4]
3 years ago
9

How do I solve this math problem?

Mathematics
2 answers:
blondinia [14]3 years ago
8 0
Subtract 1 from both sides of the equal sign. (3-11 and 11-11) So, now you only have -8 = 1/2b ... Next, divide 1/2 from both sides (because you need to make the variable, b, be the only thing on one side of the equal sign) and you get -4 = b . So, your answer is -4.
Alina [70]3 years ago
6 0
You would subtract 11 on both sides of the equation.
Then multiply the reciprocal of 1/2 which is 2.
And you should get -16 as your answer <span />
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Explain why 13233345364715 is a composite no.​
rodikova [14]

Answer:

A composite number has more than two factors.  In this case, the number 13233345364715 has more than two factors, so it is composite.  

Step-by-step explanation:

Numbers can be classified as prime or composite.  Prime numbers have only two factors, 1 and the number itself.  For example, 13 is a prime number because only 1 and 13 can be multiplied together to get 13.  However, a composite number has more than two factors.  In the case of the numer 13233345364715, I know that there are more than two factors because the number ends in 5, which means it has a factor of 5.  To confirm, divide 13233345364715/5 = 2646669072943. This large of a number may also have other factors, however, since you now know it has at least four factors, it is composite.  

6 0
3 years ago
Find the equation of the line with Slope = 6 and passing through (5,38). Write your equation in the form y =mx+b
laiz [17]

Hello.

We have:

  • A point that the line passes through
  • The slope of the line

Plug the values into the Point-Slope Formula:

\mathrm{y-y_1=m(x-x_1)}

\mathrm{y-38=6(x-5)}

\mathrm{y-38=6x-30}

\mathrm{y=6x-30+38}

\Large\boxed{\sf{ \ y=6x+8}}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

5 0
2 years ago
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Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
Solve for p 2(p + 1) = 24
Makovka662 [10]

Answer:

p=11

Step-by-step explanation:

2(p + 1) = 24

Divide each side by 2

2/2(p + 1) = 24/2

p+1 = 12

Subtract 1 from each side

p+1-1 = 12-1

p =11

4 0
3 years ago
How to write 224466 with a coma
stira [4]
224,466

hope it helps
3 0
3 years ago
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