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rodikova [14]
3 years ago
11

Find the area of a square with a side measure of 3x − 6 feet.

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Area of a square: s^2

Because we know the length of one side, we can multiply it by itself to find the area.

(3x - 6)(3x - 6)

9x^2 - 18x - 18x + 36

Combine like terms.

9x^2 - 36x + 36

<h3>The correct answer is A, or the first answer. </h3>
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The perimiter is 4 times 1 side
currently, it is 9 times 4 or 36

increased by 3
I think y mean times 3
so 9*3=27
new perimiter is 27*4=108

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5 0
3 years ago
"In quadrilateral QRST, m∠Q is 68°, m∠R is (3x + 40)°, and m∠T is (5x − 52)°. What are the measures of ∠R , ∠S , and ∠T ? Write
34kurt
TQRS is an inscribed quadrilateral.
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x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:  
m∠R, m∠S, m∠T = 112°, 112°, 68°.
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