<span>Highest point = 1406.25
Number of seconds = 9.375
We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375
So let's calculate the height at t = 9.375.
y = -16t^2 + 300t
y = -16(9.375)^2 + 300(9.375)
y = -16(87.890625) + 300(9.375)
y = -1406.25 + 2812.5
y = 1406.25
So the highest point will be 1406.25 after 9.375 seconds.
Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.'
y = -16t^2 + 300t
y = -16(9.375 + e)^2 + 300(9.375 + e)
y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e)
y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e
y = 1406.25 - 16e^2
Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
Answer:
height = 2.5 ft , base = 8 ft
Step-by-step explanation:
the area (A) of a triangle is calculated as
A = 
bh ( b is the base and h the height )
height = h then base = 2h + 3 and A = 10 , then
h(h + 3) = 10 ( multiply both sides by 2 to clear the fraction )
h(h + 3) = 20 , that is
h² + 3h = 20 ( subtract 20 from both sides )
h² + 3h - 20 = 0 ← in standard form
(h + 4)(2h - 5) = 0 ← in factored form
equate each factor to zero and solve for h
h + 4 = 0 ⇒ h = - 4
2h - 5 = 0 ⇒ 2h = 5 ⇒ h = 2.5
but h > 0 , then h = 2.5
and 2h + 3 = 2(2.5) + 3 = 5 + 3 = 8
that is height = 2.5 ft and base = 8 ft
24y*z^5/32y^2*z
24/32 = 3/4
y/y^2 = 1/y
z^5/z = z^4/1
Soo now that they are all simplified the answer is 3z^4/4y
Answer:
The square root of -100 is 10i
Step-by-step explanation:
When paired with 0.23 0.9 is a rational number
