Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
$39.50 is the final payment.
Step-by-step explanation:
0.3 x 53.95 = 16.185
53.95 - 16.185
= 37.765
0.045 x 37.765 = 1.699425 + 37.765
= 39.464425 and round
Answer:
x=-3, y=-6. (-3, -6).
Step-by-step explanation:
-4x+y=6
-5x-y=21
--------------
-9x=27
x=27/-9
x=-3
-5(-3)-y=21
15-y=21
y=15-21
y=-6
Answer:
i tried it by trial and error, and my work is below.
Step-by-step explanation:
2x + 9 = 23
subtract 9 from both sides
2x = 14
guess.... lol
x=7
43) 50% of the time, Store A has 550 or more customers per day.
44) Distribution A appears to be skewed to the left with no outliers and a center at 500 customers. Distribution B appears to be Normal with no outliers and a center at 400 customers.
45) Store A has more customers.
