Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
It's an equilateral triangle so the measure of each angle here=60 degrees
s..4x degree=15*4
hence, the value of X=15
<h2>Have a good day Ahead:)</h2>
Answer:
2 is scalene
3 is right
4 is right
5 is equalatirel
6 is scalene
7 is isocoles
8 is equalatirel
9 is right
Step-by-step explanation:
Answer:4 flowers per row
18 rows of flowers
Step-by-step explanation:
Answer:
I think it is the rectangular prism and square pyramid
Step-by-step explanation:
12x12x16=2304 it is the greatest
