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Makovka662 [10]
3 years ago
15

Catherine and Lance open a savings account at the same time. Catherine deposits $100 initially and adds $20 per week. Lance depo

sits $500 initially and adds $10 per week. Catherine wants to know when she will have the same amount in her savings account as Lance.
Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
5 0

Answer:

after 40 weeks

Step-by-step explanation:

docker41 [41]3 years ago
4 0

Answer:

After 40 weeks

Step-by-step explanation:

To get the answer to this question, we need to first know the difference in the amount of money deposited by the 2 individuals and in this case it us $400 since one deposited $500 and the other $100

The next thing to do is to divide the difference in amount(400) by the amount contributed by each person per week.

Catherine deposits $20 per week

400/20 = 20

Lance deposits $10 per week

400/10 = 40

The LCM between 40 and 20 is 40 weeks.

Therefore, both individuals need to deposit money for 40 weeks for both of their savings to be the same.

If Catherine deposits $20 for 40 weeks,she will have 40 × 20 = $800 + $100(initial deposit that she made) = $900

Lance deposits $10 for for 40 weeks and he will have 40 × 10 = $400 + $500(initial deposit made by him)= $900

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The bus company charges $2.95 per mile for each bus. What is the cost for all 6 buses to drive 124 mile trip?
Softa [21]

Answer:

2194.8

First, 124 times 2.95 then you get 365.8 and finally you multiply by 6 and get you answer.

6 0
3 years ago
Consider the hypothesis test below.
Pavel [41]

Answer:

Z_{H0} =1.79

p-value: 0.0367

Decision: Reject H₀

Step-by-step explanation:

Hello!

Hypothesis to test:

H₀:ρ₁-ρ₂=0

H₁:ρ₁-ρ₂>0

The statistic to use to test the difference between two population proportions is the approximation of Z

Z=<u>     (^ρ₁-^ρ₂)-(ρ₁-ρ₂)     </u>   ≈N(0;1)

   √ (<u>^ρ₁(1-^ρ₁))/n₁)+(^ρ₂(1-^ρ₂)/n₂))</u>

                   

Z=<u>                    (0.28-0.15)-0                    </u>= 1.79

   √ (<u>0.28(1-0.28)/200)+(0.15(1-0.15)/300)</u>

p-value

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

P(Z>1.79)= 0.0367

Conclusion:

Comparing the p-value against the significance level, you can decide to reject the null hypothesis.

I hope you have a SUPER day!

8 0
3 years ago
a taxi ride costs 40 dollars for the first 500 meters and each additional 300 meters (or a fraction thereof) adds $3.50 to the f
Colt1911 [192]

Answer:

$ 71.5

Step-by-step explanation:

firstly kilometer to meters

<em>1 km = 1000 m </em>

therefore 3 km = 3000m

for the first 500 = $40

hence deduct the 500 from 3000m

3000 - 500 = 2500

now find out how many 300m go into 2500

2500 / 300 = 8.33

which is rounded up to 9

therefore the total amount is :

40 + 9 * 3.5

<u>= $71.5</u>

<u></u>

5 0
3 years ago
Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of seconds for a randomly selected lap.

The random variable <em>X </em>is normally distributed with mean, <em>μ</em> = 129.71 seconds and standard deviation, <em>σ</em> = 2.28 seconds.

Thus, X\sim N(129.71,\ 2.28^{2}).

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

P(X

                   =P(Z

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let <em>x</em> represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of <em>z</em> for the above probability is:

<em>z</em> = -1.88

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let <em>x</em>₁ and <em>x</em>₂ be the values between which the middle 80% of the distribution lie.

That is,

P(x_{1}

The value of <em>z</em> for the above probability is:

<em>z</em> = 1.28

Compute the values of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80               z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63

Thus, the middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

5 0
3 years ago
There were 3 apple, 1 mixed fruit, 2 grape, and 4 tropical fruit juice boxes in the cooler at the picnic. What is the probabilit
Agata [3.3K]
There are total 10 juice boxes
P(grape) first pick:
2/10=1/5
P(grape) second pick:
1/9
As a result, the probability that, when Jill reaches into the cooler to grab two juice boxes without replacing them, she grabs two that are grape is 1/45. Hope it help!
8 0
3 years ago
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