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3 years ago

Image down below plz help

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

I feel strongly that it is A.

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Solve for x ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎ ‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎

Pie

Answer:

18.46

Step-by-step explanation:

find the area using SSS, then solve for height

3 0

2 years ago

Is 6+2 +4x equivalent to 6- ( 2-4x) . if not , why not ?

Xelga [282]

Well lets solve for both.
6 + 2 + 4x
Combine like terms.
8 + 4x
Now solve the other one.
6 - (2 - 4x)
Distribute.
6 - 2 + 4x
Combine like terms.
4 + 4x.
These equations are not equivalent because instead of adding two, like in the first one, the second problem is subtracting. So you get 8 + 4x and 4 + 4x. I hope this helps love! :)

6 0

3 years ago

Describe what your first step would be to solve the equation below : <br> 2 (x+7) = -4x + 14

Andrej [43]

Answer:

The first step to solve the equation below is to first distribute the 2 to (x+7)

Step-by-step explanation:

2 (x+7) = -4x + 14

2x + 14 = -4x + 14

3 0

3 years ago

Read 2 more answers

Consider the equation below -2(5x + 8) = 14 + 6x complete the statements below with the process used to achieve steps 1-4

Ad libitum [116K]

Step-by-step explanation:

1. Distribute the -2. multiply-2 with 5x and 8. it will be -10x-16=14+6x. For me, i make small numbers negative or positive than big ones. Add 16 to both sides. it will be -10x=30+6x. Subtract 6x. -10x-6x=-16x. Divide both sides by 16. x=30/16= 1 and 14/16

6 0

3 years ago