Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
By definition, the area of a rectangle is given by:
A = (width) * (long)
Substituting values we have:
750 = (y-5) * (y)
Rewriting we have:
750 = y ^ 2 - 5y
y ^ 2 - 5y - 750 = 0
Answer:
An equation that can be used to solve for And the length of the room is:
y ^ 2 - 5y - 750 = 0
Hello,
cos 160°=-q
cos 20°=-cos 160°=q
sin 20°=√(1-q²)=sin 160°
tan -20°=tan 160=√(1-q²)/-q
cos 70°=sin 20°=√(1-q²)
Answer:
look down
Step-by-step explanation:
OK so u take something like 9/3 and then ask how many times the 3 goes into the 9 and that is your whole number. whatever is left is your top of the fraction and the bottom stays the same hope this helped
Answer:
the answer 61 cups of chocolate
Step-by-step explanation:
briniest please
