Need help with 5 and 6 will give branliest to the first to answer
2 answers:
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Step-by-step explanation:
How to find inverse function:
Step 1: Write down equation.
Remeber Ruler notation that
f(x)=y so we replace y with f(x).
Next, we must isolate x so first we subtract 3.
Divide both sides by 4.
Remeber that sin^-1x and sin x are inverse functions so they will cancel out to x. So we get
Swap x and y. So our inverse function is
If you want another proof: Here's one,
Let plug an a x value for the orginal equation,
4 sin x+3. Let say that
We then would get
So when x=pi/2, y=7.
By definition of a inverse function, if we let 7 be our input, we should get pi/2. as a output.
So let see.
So this is the inverse function of 4 sin x+3.
1b. The range of f(x) is [-1,7).
We can use transformations to describe range.
We have
Parent function is
with a range of [-1,1].
We then vertical stretch by 4 so we get
and our range will be
[-4,4].
Then we add a vertical shift of 3.
So our range of 4 sin x+3.
[-1,7].
1c. Domain of a inverse function is the range of the orginal function.
The range of f(x) is [-1,7) so the domain of f^-1(x) is [-1,7].
f(x) domain was restricted to -pi/2 to pi/2 so the range of f^-1(x) is [-pi/2, pi/2]