Given: h(t) = 25 - a·t²
h(0.5) = 21
Find: t such that h(t) = 0
Solution: h(0.5) = 25 - a·0.5² = 21
25 - 21 = a/4
4·4 = a = 16
Then
h(t) = 25 - 16t²
We want h(t) = 0, so
0 = 25 - 16t²
16t² = 25
t² = 25/16 = (5/4)²
t = 5/4 = 1.25
It takes 1.25 seconds for the entire 25 ft drop.
In this question, we're trying to find how many hours Mike had the bike for.
We know that 13 dollars as a flat rate.
We also know that they charge 13 dollars and hour.
Mike paid a total of 67 dollars for the bike.
Lets represent this as an equation:
67 = 9x + 13
x = hours the bike was rented
Solve for x:
67 = 9x + 13
Subtract 13 from both sides
54 = 9x
Divide both sides by 9
6 = x
This means that Mike rented the bike for 6 hours.
Answer:
6 hours
That doesn’t make sense. Did you mean 15?
It’s b. :) hope this helps you
I got -6/25 Sorry I can't really explain this try web2.0calc.com it helps alot with math.