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ANTONII [103]
2 years ago
14

a particular plant root grows 1.5 inches per month how many centimeters is in the plant root growing per month 1 in equals 2.54

cm ​
Mathematics
2 answers:
Alja [10]2 years ago
8 0

Answer:

if i get this wrong sorry

Step-by-step explanation:

2.5 inches is 6.35 centimeters because 1 inch is 2.54 cm

Natalija [7]2 years ago
5 0

Answer:

hey guys join me

not for bad purpose

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for good purpose only

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What is the missing constant term in the perfect square that starts with x2 – 16x?
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Answer:

64

Step-by-step explanation:

the expression is

x² - 16x + _

the constant term is the square of the number residing with x divided by 2

the number number x = 16

therefore the constant term is (16/ 2)²

= 8²

= 64

the formula being used here is

(x + a)² = x² + 2ax + a²

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Semmy [17]

The area of rectangular garden is 8 x^{2}+4 x-24

<h3><u>Solution:</u></h3>

Given that a rectangular garden has width = 4x - 6

Length of rectangular garden = 2x + 4

To find: area of rectangular garden

<em><u>The area of rectangle is given as:</u></em>

\text {area of rectangle }=\text { length } \times \text { width }

Substituting the values in given formula,

\begin{array}{l}{\text { area of rectangle }=(2x+4) \times(4x-6)} \\\\ {=8 x^{2}-12 x+16 x-24} \\\\ {=8 x^{2}+4 x-24}\end{array}

Thus the area of rectangular garden is 8 x^{2}+4 x-24

3 0
3 years ago
on square bcde if e is located at (4,-9) and d is located at (10,-5) find the perimeter of the square
mariarad [96]

Answer:

  • 8\sqrt{13} units

Step-by-step explanation:

<u>We know that:</u>

  • P = 4a

<u>We can find one side by distance formula:</u>

  • a = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • a = \sqrt{(10 - 4)^2+(-5+9)^2} = \sqrt{36+16} = \sqrt{52} = 2\sqrt{13}

<u>Then the perimeter is:</u>

  • P = 4*2\sqrt{13} = 8\sqrt{13} units
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3 years ago
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