Question

PLZ HELP ASAP! WILL MARK BRAINLIEST! HURRYYY! Mary went to the circus. During the dog show, she counted 54 legs between the dogs and the trainers who were having the dogs perform their amazing tricks. If there were a total of 15 dogs and trainers in the performance, how many of each were there?

Answer 1

Answer:

Three ppl, Twelve dogs

Step-by-step explanation

x=hoomans

y=doggos

x+y=15

2x+4y=54

x=15-y

2(15-y)+4y=54

30-2y+4y=54

2y=24

y=12

so that means there are 12 doggos

and since x=15-y, which is 15-12, which is 3,

there are three hoomans

Answer 2

Answer:

three ppl, Twelve dogs

Step-by-step explanation: