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3 years ago

What is the radius of polygon JKLMN ?

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

Radius of the circle is 5 units.

Step-by-step explanation:

JKLMN is a regular polygon inscribed in a circle.

Since, its a regular polygon,

JN = NM = 5.88 units

"Perpendicular drawn from the center of the circle to any chord is the bisector of the chord"

Therefore, PQ will be the perpendicular bisector of chord NM.

QM = $\frac{1}{2}(NM)$

QM = $\frac{1}{2}(5.88)$

QM = 2.94 units

By applying Pythagoras theorem in ΔPQM,

PM² = PQ² + QM²

PM² = (4.05)² + (2.94)²

PM = $\sqrt{16.4025+8.6436}$

PM = $\sqrt{25.0461}$

PM = 5 units

Therefore, radius of the circle is 5 units.

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3 years ago

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He ran 3.25 on Tuesday

Step-by-step explanation:

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3 years ago

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Can anyone help with the answers to all these questions with an explanation please?

saveliy_v [14]

ANSWER:

1) 25.70 cm 2) 30.84 cm 3) 10.71 km 4) 1.07 km 5) 6.71 cm 6) 10.07 mm

EXPLANATION:

1. Know that the circumference formula for a full circle is:

$C = 2\pi r$

The value of pi ( $\pi$ ) = 3.14

The radius ( $r$ ) will be given in the diagrams.

2. Now we can figure out the perimeters.

Shape One: Semi-circle

C = 2 x 3.14 x 5

C = 31.4 cm

Divide the circumference by 2 because it is a semi-circle. Then add 10 cm to this (because the flat side is 10 cm).

P = $\frac{31.4}{2} +10$

P = 25.7 cm ≈ 25.70 cm

Shape Two: Semi-circle

C = 2 x 3.14 x 6 (the picture shows the diameter so we need to half that to get the radius)

C = 37.68 cm

Divide the circumference by 2 because it is a semi-circle. Then add 12 cm to this (because the flat side is 12 cm).

P = $\frac{37.68}{2}+12$

P = 30.84 cm

Shape Three: Quadrant

C = 2 x 3.14 x 3

C = 18.84 km

Divide the circumference by 4 because it is a quadrant. Then add 6 km to this (because the two flat sides are 3 km each and so it is 6 km total).

P = $\frac{18.84}{4} +6$

P = 10.71 km

Shape Four: Quadrant

C = 2 x 3.14 x 0.3

C = 1.884 km

Divide the circumference by 4 because it is a quadrant. Then add 0.6 to this (because the two flat sides are 0.3 km each and so it is 0.6 km total).

P = $\frac{1.884}{4} + 0.6$

P = 1.071 km ≈ 1.07 km

Shape Five

C = 2 x 3.14 x 1

C = 6.28 cm

For this shape, we need to subtract the circumference of the missing sector from the circumference of the full circle to obtain the circumference for this shape. So, the circumference for the shape would be:

C = $6.28 - \frac{6.28}{4}$

C = 6.28 - 1.57

C = 4.71 cm

Then add the flat sides (1 cm + 1 cm = 2 cm) to this circumference to get the perimeter.

P = 4.71 + 2

P = 6.71 cm

Shape Six

C = 2 x 3.14 x 1.5 (Divide the 3 mm diameter by 2 to get the radius)

C = 9.42 cm

Do the same thing you did for Shape 5.

C = $9.42 - \frac{9.42}{4}$

C = 7.065 mm

Then add the flat sides (1.5 + 1.5 = 3) to this circumference.

P = 7.065 + 3

P = 10.065 mm ≈ 10.07 mm

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