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DanielleElmas [232]
2 years ago
13

Select the quadrant or axis on which you would find the point (-3,-5).

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
6 0

Answer:

Quadrant 3

Step-by-step explanation:

Since both x and y are negative, you go to the quadrant which has both negatives, meaning Q3

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Complete the equation of the line through (-9,-9) and (-6,0)
Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3

Thus, the equation is of the form:

y = 3x + b

We substitute one of the points and find b:

0 = 3 (-6) + b\\0 = -18 + b\\b = 18

Finally, the equation is:

y = 3x + 18

Answer:

y = 3x + 18

7 0
3 years ago
Solve the right triangle. round your answer to the nearest tenth​
mrs_skeptik [129]

Answer:

?

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP! Screenshot attached
nadya68 [22]

Answer:

( x - 6 ) ( x - 3 ) (x + 4)

Step-by-step explanation:


6 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
Casey wants to buy a gym membership. One gym has a $176 joining fee and costs $29 per month. Another gym has no joining fee and
kaheart [24]

Answer:

8 months for cost to be same, cost will be $408

Step-by-step explanation:

x = months

176 + 29x = 0 + 51x

176 = 22x

8 = x

176 + (29*8) = 408

0 + (51*8) = 408

3 0
3 years ago
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