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3 years ago

If f(x)=x²-x what is f(-5)?

Mathematics

1 answer:

joja [24]3 years ago

7 0

Answer:

f(-5)=30

Step-by-step explanation:

in this scenario you want to plug in -5 for x which will give you an equation of f(-5)=(-5)^2+5 which evaluates to 30

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Dr. Tu must administer emergency medicine to his patient, Mrs. Jones. The

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Answer:

168

Step-by-step explanation: You would do 140/100 = 1.4 then multiply 120 by 1.4 which is 168.

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3 years ago

The difference between John and

ddd [48]

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$46,130,75 or $43,869.25

Step-by-step explanation:

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3 years ago

Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b

Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

Step-by-step explanation:

We are given the following in the question:

$p(x) = 0.1 e^{-0.1x}$

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

$=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%$

b) P(calls last 4 minutes or more)

$=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%$

c) cumulative distribution function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

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4 years ago

What is 5 divided by 4/3

Diano4ka-milaya [45]

3.75 as a decimal, 3 &3/4 as a fraction

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3 years ago

Read 2 more answers

The function below models the voltage, in volts, of a certain alternating current after x seconds, where A and b are positive co

Katarina [22]

First of all, we can just ignore A, it has no effect but to vertically stretch our cosine.

If it was only $f(x)=cosx$ , the function would be invertible as long as it's confined between $0$ and $\pi$ . Now, the argument of our cosine is not $x$ but $bx$ . It means that it won't stop at $\pi$ , but at $\frac{\pi}{b}$ .

Another way to think about it, "what should i replace x with so I get $\pi$ inside the cosine?"

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3 years ago

If f(x)=x²-x what is f(-5)?​

If f(x)=x²-x what is f(-5)?