Answer:
$46.43
Step-by-step explanation:
First, let's use the compound amount equation,
A = P(1+r/n)^(nt), where P is the principal, r is the annual interest rate as a decimal fraction, n is the # of compounding periods per year, and t is the number of years.
Here,
A = $600(1 + 0.05/4)^(4*[1 1/2]). Let's evaluate this:
A = $600*(1.0125)^6
= $646.43.
This is the amount due after 1.5 years if $600 were the original principal borrowed.
If you want ONLY the compound interest, subtract $600 from $646.43:
Compound interest was $46.43.
Answer:C
Step-by-step explanation:
C
Step-by-step explanation:
![\text{Use:}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\left(\dfrac{1}{a}\right)^n\\\\=============================](https://tex.z-dn.net/?f=%5Ctext%7BUse%3A%7D%5C%5C%5C%5Ca%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%5Cdfrac%7Ba%5En%7D%7Ba%5Em%7D%3Da%5E%7Bn-m%7D%5C%5C%5C%5C%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5Ca%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7Ba%7D%5Cright%29%5En%5C%5C%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![A.\ \dfrac{5^3}{5^6}=5^{3-6}=5^{-3}=\left(\dfrac{1}{5}\right)^3\\\\B.\ (14^3)^6=14^{3\cdot6}=14^{18}\\\\C.\ 8^3\cdot8^6=8^{3+6}=8^9\\\\D.\ \dfrac{16^6}{16^3}=16^{6-3}=16^3\\\\E.\ (21^3)^{-6}=21^{3\cdot(-6)}=21^{-18}=\left(\dfrac{1}{21}\right)^{18}\\\\F.\ 100^0=1\\\\G.\ \dfrac{\left(\frac{2}{5}\right)^8}{\left(\frac{2}{5}\right)^6}=\left(\dfrac{2}{5}\right)^{8-6}=\left(\dfrac{2}{5}\right)^2\\\\H.\ (0.15)^{-2}\cdot(0.15)^4=(0.15)^{-2+4}=(0.15)^2\\\\I.\ 7^{-5}=\left(\dfrac{1}{7}\right)^5](https://tex.z-dn.net/?f=A.%5C%20%5Cdfrac%7B5%5E3%7D%7B5%5E6%7D%3D5%5E%7B3-6%7D%3D5%5E%7B-3%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B5%7D%5Cright%29%5E3%5C%5C%5C%5CB.%5C%20%2814%5E3%29%5E6%3D14%5E%7B3%5Ccdot6%7D%3D14%5E%7B18%7D%5C%5C%5C%5CC.%5C%208%5E3%5Ccdot8%5E6%3D8%5E%7B3%2B6%7D%3D8%5E9%5C%5C%5C%5CD.%5C%20%5Cdfrac%7B16%5E6%7D%7B16%5E3%7D%3D16%5E%7B6-3%7D%3D16%5E3%5C%5C%5C%5CE.%5C%20%2821%5E3%29%5E%7B-6%7D%3D21%5E%7B3%5Ccdot%28-6%29%7D%3D21%5E%7B-18%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B21%7D%5Cright%29%5E%7B18%7D%5C%5C%5C%5CF.%5C%20100%5E0%3D1%5C%5C%5C%5CG.%5C%20%5Cdfrac%7B%5Cleft%28%5Cfrac%7B2%7D%7B5%7D%5Cright%29%5E8%7D%7B%5Cleft%28%5Cfrac%7B2%7D%7B5%7D%5Cright%29%5E6%7D%3D%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E%7B8-6%7D%3D%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E2%5C%5C%5C%5CH.%5C%20%280.15%29%5E%7B-2%7D%5Ccdot%280.15%29%5E4%3D%280.15%29%5E%7B-2%2B4%7D%3D%280.15%29%5E2%5C%5C%5C%5CI.%5C%207%5E%7B-5%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B7%7D%5Cright%29%5E5)
![J.\ 4\cdot4^3=4^{1+3}=4^4](https://tex.z-dn.net/?f=J.%5C%204%5Ccdot4%5E3%3D4%5E%7B1%2B3%7D%3D4%5E4)
If you draw a grid/graph and you placed the point (-1,-12) you just have to go the right 11 times and you should get (10,-12), make sure you only go right and not go up or down.
So the answer is (10,-12)