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konstantin123 [22]
3 years ago
13

If f(x)=x²-x what is f(-5)?​

Mathematics
1 answer:
joja [24]3 years ago
7 0

Answer:

f(-5)=30

Step-by-step explanation:

in this scenario you want to plug in -5 for x which will give you an equation of f(-5)=(-5)^2+5 which evaluates to 30

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Given isosceles trapezoid TRHY, in units what is the length of b2 if the height is 13 units, b1 is 21 units, and the area is 215
GenaCL600 [577]

We are given a trapezoid TRHY.

Height of the trapezoid = 13 units.

b1 = 21 units and

Area = 215 units squares.

We need to find the length of b2.

We know formula for area of a trapezoid.

A= \frac{1}{2} (b1+b2)\times h

Plugging values in formula.

215 = \frac{1}{2}(21+b2)× 13.

215 = 6.5(21+b2)

Dividing both sides by 6.5, we get

\frac{215}{6.5}=\frac{6.5(21+b2)}{6.5}

33.08 = 21+b2.

Subtracting 21 from both sides, we get

33.08-21 = 21-21+b2

b2 = 12.08.

<h3>Therefore,  length of b2 is 12.08 units.</h3>
4 0
3 years ago
In the city, the dust and between the library and the police station is 3 miles less than twice the distance between the police
alina1380 [7]

Answer:

7 miles

Step-by-step explanation:

Let's call the distance between the library and police station x. Then, the distance between the police station and fire station would be 3 less than twice x. Twice means multiply by 2 so twice x is 2 * x = 2x and 3 less than means that you subtract 3 so 3 less than 2x is 2x - 3. Now, we know that x = 5 so all we have to do now is substitute x = 5 into 2x - 3, therefore, the answer is 2 * 5 - 3 = 7 miles.

4 0
3 years ago
The roof of a tower in a castle is shaped like a cone. The height of the roof is 30 ft, and the radius of the base is 15 ft. Wha
xz_007 [3.2K]

Answer:

The area of the roof: ≈2287.44 ft^2, the lateral area of the roof:≈1580.58 ft^2

Step-by-step explanation:

The area of the roof is computed by the equation of the area of a cone:
A = πr(r + \sqrt{h^{2}+r^(2) })
(r: radius, h: height, πr^2 is the area of the base of the cone, πr\sqrt{h^{2}+r^(2) } is the lateral area of the cone). So:

A = 15\pi (15 + \sqrt{30^{2} +15^{2}  } ) ≈ 2287.44 ft^2.

As I stated earlier, the lateral area of the roof can be computed:

AL=15\pi \sqrt{30^{2} +15^{2} } ≈ 1580.58 ft^2.

5 0
3 years ago
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