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borishaifa [10]

3 years ago

15

You are choosing a card from a standard deck of cards. The probability of a red card is 1 2 . The probability of a heart is 1 4

. The probability of a 7 is 1 13 . The probability of a 7 of hearts is 1 52 . Which is the MOST likely to happen?

1 answer:

devlian [24]3 years ago

8 0

Answer:

you probable going to pick the red card

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Rick is going to wawa for lunch. He has to choose between two coupons, 25% off his purchase or 5$ off his orders. If his cheeses

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Answer:

Step-by-step explanation:

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3 years ago

The difference between a number and 22 is 57. what is the number

Ksju [112]

Answer:

79

Step-by-step explanation:

The difference between 79 and 22 is 57. 79 is THE number. All you have to do is add 22 and 57 because the answer you get would ALWAYS have one of the numbers added as the difference.

5 0

3 years ago

Read 2 more answers

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

How do you turn 53 1/3 into a fraction????

goldfiish [28.3K]

160/3 is 53 1/3 as a fraction

7 0

3 years ago

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Question in pic, will mark brainliest.

bulgar [2K]

Answer:

See explanation

Step-by-step explanation:

Consider triangles ABC and DEC. In these triangles,

$\overline{BC}\cong \overline {EC}$ - given
$\overline{AC}\cong \overline {DC}$ - given;
$\angle ACB\cong \angke DCE$ as vertical angles.

So,

$\triangle ABC\cong \triangle DEC$ by SAS postulate (two sides and angle between these sides of one triangle are congruent to two sides and angle between these sides of another triangle, so triangles are congruent).

Congruent triangles have congruent corresponding parts, hence,

$\overline{BA}\cong \overline{ED}$

3 0

3 years ago