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Leona [35]
2 years ago
11

Using planck's constant and a wavelength of 656e-9 what is the energy of the photon

Physics
1 answer:
lbvjy [14]2 years ago
4 0

Answer:

3.03e-19 J

Explanation:

Use the formula E = hc/λ

Where:

h (Planck's constant) = 6.626e-34 J*s

c (speed of light, constant) = 3.00e8 m/s

λ (wavelength) = 656e-9 m

E = energy (in Joules)

E = (6.626e-34 * 3.00e8) / 656e-9 = 3.03018293e-19 = 3.03e-19 J

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A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
galina1969 [7]

Answer:

Force on the proton will be .73\times 10^{-14}N

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light c=3\times 10^8m/sec

So speed of proton v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec

Magnetic field B = 0.00629 T

Charge on proton q=1.6\times 10^{-16}C

Angle between velocity and magnetic field \Theta =137^{\circ}

Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

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3 years ago
Edward with it gathering physical evidence at the scene of a crime. He finds a fingerprint pressed into the wax of the candle. W
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Answer:trace

Explanation:

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3 years ago
Read 2 more answers
Dependent variable is the _______ that happens because of the UI independent variable. (No answer choices provided)
Damm [24]

Answer: One is called the dependent variable and the other the independent variable. The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable.

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3 years ago
un columpio de balancin tiene una barra de 6m de longitud y en ella se sientan 2 personas,una de 60kg y otra de 40kg, calcular e
Kitty [74]

Answer:

<em>El punto de apoyo debe colocarse a 3.6 metros de la persona de 40 Kg</em>

<em>La ventaja mecánica es 1.5</em>

Explanation:

<u>Máquinas Simples</u>

Un balancín es un ejemplo de máquina simple, donde se aplica una fuerza física y ésta puede amplificarse o reducirse a voluntad cambiando la configuración física de la máquina.

En nuestro caso, el punto de apoyo o fulcro se coloca entre las dos fuerzas constituyendo una máquina de primer grado.

La situación planteada se muesta en la figura anexa. Debemos averiguar el valor de x para que las dos personas sentadas en el balancín puedan estar en equilibrio.

Para determinar el valor de x, se establece la condición de equilibrio de torques mecánicos. Ya que el balancín se asume en reposo, los torques aplicados de cada lado del mismo deben ser iguales, haciendo que el torque neto sea cero.

El torque es el producto de la fuerza por la distancia:

T = F.d

De cada extremo del balancín, se aplica una fuerza igual al peso de cada persona, es decir, llamando F1 al peso de la persona de 40 Kg y F2 al peso de la persona de 60 Kg:

F_1 = 40 kg * 9.8 m/s^2=392N\\\\F_2 = 60 kg * 9.8 m/s^2=588 N

El torque neto del balancín debe ser cero, es decir (refiérase a la figura):

F_1*x=F_2*(6-x)

Reemplazando los valores obtenidos:

392*x=588*(6-x)

Operando:

392*x+588*x=588*6

Simplificando

980*x=3528

Resolviendo

\displaystyle x=\frac{3528}{980}=3.6\ m

El punto de apoyo debe colocarse a 3.6 metros de la persona de 40 Kg, es decir, a (6 - 3.6) = 2.4 metros de la persona de 60 Kg

La ventaja mecánica se calcula como el cociente de ambas distancias

\displaystyle VM=\frac{3.6}{2.4}=1.5

La ventaja mecánica es 1.5, es decir, se amplifica la fuerza vez y media

3 0
3 years ago
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