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Leona [35]
2 years ago
11

Using planck's constant and a wavelength of 656e-9 what is the energy of the photon

Physics
1 answer:
lbvjy [14]2 years ago
4 0

Answer:

3.03e-19 J

Explanation:

Use the formula E = hc/λ

Where:

h (Planck's constant) = 6.626e-34 J*s

c (speed of light, constant) = 3.00e8 m/s

λ (wavelength) = 656e-9 m

E = energy (in Joules)

E = (6.626e-34 * 3.00e8) / 656e-9 = 3.03018293e-19 = 3.03e-19 J

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The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

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Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

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From the above calculation, we can conclude that the current in wire 3 is  I₃ = 0.33 A

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brainly.com/question/25537936

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