1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jarptica [38.1K]
2 years ago
9

Write a note on unity of ant​

Physics
1 answer:
Tom [10]2 years ago
3 0

Answer: When a pathogen enters their colony, ants change their behavior to avoid the outbreak of disease. In this way, they protect the queen, brood and young workers from becoming ill. These results, from a study carried out in collaboration between the groups of Sylvia Cremer at the Institute of Science and Technology Austria (IST Austria) and of Laurent Keller at the University of Lausanne, are published today in the journal Science.

Explanation: search for it.

You might be interested in
He user of a machine applies force to the machine over the _____ distance.
gtnhenbr [62]
The blank distance is your answer

5 0
3 years ago
With the same block-spring system from above, imagine doubling the displacement of the block to start the motion. By what factor
Fofino [41]

Answer:

A)     K / K₀ = 4   b)     v / v₀ = 4

Explanation:

A) For this exercise we can use the conservation of mechanical energy

in the problem it indicates that the displacement was doubled (x = 2xo)

starting point. At the position of maximum displacement

      Em₀ = Ke = ½ k (2x₀)²

final point. In the equilibrium position

      Em_{f} = K = ½ m v²

        Em₀ = Em_{f}

        ½ k 4 x₀² = K

        (½ K x₀²) = K₀

         K = 4 K₀

          K / K₀ = 4

B) the speed value

          ½ k 4 x₀² = ½ m v²

          v = 4 (k / m) x₀

if we call

           v₀ = k / m x₀

          v = 4 v₀

         v / v₀ = 4

3 0
3 years ago
Which line represents a stationary object?
sineoko [7]

Answer:

I think its B but I may be wrong

3 0
3 years ago
Read 2 more answers
How much force is required to accelerate a 2kg mass at 3 m/s2? answer key?
mr Goodwill [35]
F = ma so u can plug in the given numbers and solve:

F = (2)(3)
4 0
3 years ago
A concave mirror has a focal length of 13.5 cm. This mirror forms an image located 37.5 cm in front of the mirror. Find the magn
77julia77 [94]

Explanation:

It is given that,

Focal length of the concave mirror, f = -13.5 cm

Image distance, v = -37.5 cm (in front of mirror)

Let u is the object distance. It can be calculated using the mirror's formula as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{(-13.5)}-\dfrac{1}{(-37.5)}

u = -21.09 cm

The magnification of the mirror is given by :

m=\dfrac{-v}{u}

m=\dfrac{-(-37.5)}{(-21.09)}

m = -1.77

So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.

7 0
3 years ago
Other questions:
  • State Newtons first law of motion.
    12·1 answer
  • It is easy to jump on a smooth surface than of cemented surface
    12·1 answer
  • A student submerges an irregularly object in a graduated cylinder half filled with water. The level of the water in the cylinder
    15·1 answer
  • During an experiment, a student moved a cell from pure water to salted water. What will most likely happen to the cell?
    10·1 answer
  • Which of the following are not likely to form bonds?
    8·2 answers
  • 2. The length of a day is based on the amount of time that
    9·1 answer
  • What is the electric potential 15 cm above the center of a uniform charge density disk of total charge 10 nC and radius 20 cm?
    10·2 answers
  • A spring oscillates with a period of<br> 0.228 S. What is its frequency?<br> (Unit = Hz)
    5·1 answer
  • Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the
    5·1 answer
  • Which of these units is most appropriate to use when measuring the mass of a person?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!