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Nutka1998 [239]
3 years ago
6

The expressions below represent either exponential growth or exponential decay. Check all the expressions that represent exponen

tial decay.
5^x
3(0.75)^2t
35(2.4)^x
5000(1.04)^3t
0.05^x
500(0.005)^t
Mathematics
1 answer:
asambeis [7]3 years ago
6 0

Answer:

Answers B, E and F (1, 5 and 6).

Step-by-step explanation:

In an exponential equation, (y=ab^x), the "b" value must be a decimal less than 1 (but greater than 0) for it to be considered an exponential decay function. Only equations B, E and F have a "b" value that fits this criteria.

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Best and correct answer gets brainliest!!!
dmitriy555 [2]
59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
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8 0
3 years ago
Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c
steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

Compute the sample proportions as follows:

\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23

The critical value of <em>z</em> for 90% confidence interval is:

z_{0.10/2}=z_{0.05}=1.645

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0
3 years ago
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